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erik [133]
4 years ago
5

Please help me I really don’t get this so please help me

Mathematics
1 answer:
ludmilkaskok [199]4 years ago
3 0

Answer:

5

Step-by-step explanation:

As an example, let's divide 0.75 by 0.15.  Multiply both numerator and denom. by 100, obtaining 75 / 15.  Here we don't have to worry about decimal points any longer.  Using a calculator or long division, you can show that 75 / 15 = 5, which is the same result if you "did" 0.75 / 0.15.

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What's the intuition behind the equation 1+2+3+⋯=−1121+2+3+⋯=−112 ?
Aleks [24]
The sum clearly diverges. This is indisputable. The point of the claim above, that

1+2+3+\cdots=-\dfrac1{12}

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.

The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it C. Then

\begin{matrix}C&=&1&+2&+3&+4&+5&+6&+\cdots\\4C&=&&+4&&+8&&+12&+\cdots\\-3C&=&1&-2&+3&-4&+5&-6&+\cdots\end{matrix}

Now, recall the geometric power series

\displaystyle\sum_{n\ge0}x^n=1+x+x^2+x^3+\cdots=\dfrac1{1-x}

which holds for any |x|. It has derivative

\displaystyle\sum_{n\ge1}nx^{n-1}=1+2x+3x^2+4x^3+\cdots=\dfrac1{(1-x)^2}

Taking x=-1, we end up with

1+2(-1)+3(-1)^2+4(-1)^3+\cdots=1-2+3-4+\cdots=\dfrac14

and so

-3C=\dfrac14\implies C=-\dfrac1{12}

But as mentioned above, neither power series converges unless |x|. What Ramanujan did was to consider the sum 1-2+3-4+\cdots as a limit of the power series evaluated at x=-1:

\displaystyle-3C=\lim_{x\to-1^+}\sum_{n\ge1}nx^{n-1}=\lim_{x\to-1^+}\frac1{(1-x)^2}=\frac14

then arrived at the conclusion that C=-\dfrac1{12}.

But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.
4 0
3 years ago
Suppose that you collect data for 15 samples of 30 units each, and find that on average, 2.5 percent of the products are defecti
Korvikt [17]

Answer:

The  UCL  is  UCL  =  0.054

The LCL  is  LCL \approx 0

Step-by-step explanation:

From the question we are told that  

     The quantity of each sample is  n =  30

     The  average of defective products is  p  =  0.025

Now  the upper control limit [UCL] is  mathematically represented as

       

      UCL  = p +  3 \sqrt{\frac{p(1-p)}{n}  }

substituting values  

      UCL  = 0.025 +  3 \sqrt{\frac{0.025 (1-0.025)}{30}  }

      UCL  =  0.054

The  upper control limit (LCL) is mathematically represented as

       LCL  = p -  3 \sqrt{\frac{p(1-p)}{n}  }

substituting values  

      LCL  = 0.025 -  3 \sqrt{\frac{0.025 (1-0.025)}{30}  }

       LCL  = -0.004

        LCL \approx 0

       

8 0
3 years ago
Which congruence theorem can be used to prove △WXS ≅ △YZS? Triangles W X S and Y Z S are connected at point S. Angles W X S and
iVinArrow [24]

Point S makes the two connected angles the same. They both have right angles.

And one side of each is congruent.

This means you know 2 angles are the same and one side is the same.

You would use ASA (Angle, Side, Angle)

3 0
3 years ago
Read 2 more answers
Which graph represents f(x) =3(2)^x
boyakko [2]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Use the picture below.
Flauer [41]

Answer:

x = 2.67°

GKJ = 40°

Step-by-step explanation:

Angle HKJ = 6x + 4

Angle HKG = 9x - 4

Segment bisects Angle GKJ, it means that angle HKJ is the same as angle HKG.

You have the measure of both angles in terms of x.

Angle HKJ = Angle HKG

6x + 4 = 9x - 4

4 + 4 = 9x - 6x

8 = 3x

2.67 = x

Angle HKJ:

6(2.67) + 4 = 20°

Angle HKG:

9(2.67) - 4 = 20°

Angle GKJ = HKJ + HKG = 20 + 20 = 40°

6 0
3 years ago
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