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Alex787 [66]
3 years ago
5

Triangle ABC is congruent to A'BC' by the HL theorem What single rigid transformation maps ABC onto A'BC'?

Mathematics
2 answers:
larisa [96]3 years ago
4 0

Answer:

b. reflection

Step-by-step explanation:

just took the test

nikklg [1K]3 years ago
4 0

Answer:

b is the Answer

Step-by-step explanation:

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A cylindrical rain barrel has a radius of 2 feet and holds a total of 30 cubic feet of water. How tall is the rain barrel? Use 3
enot [183]

Answer:

2.39 feet

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2}h

where

r is the radius of the base of the cylinder

h is the height of the cylinder

we have

V=30\ ft^3

r=2\ ft

\pi =3.14

substitute

30=(3.14)(2^{2})h

Solve for h

30=(3.14)(4)h

h=30/12.56

h=2.39\ ft

7 0
3 years ago
Vanessa deposited money into a bank account that earned 1.25% simple interest each year. After 1212 year, she had earned $5.00 i
Reil [10]
I=prt,,5.00=.0125*1212p,,p=5.00/.0125*1212=?? Use the calculator
3 0
3 years ago
Write the expression as either the sine, cosine, or tangent of a single angle. tan5x - tan2y / 1 + tan5x tan2y
Kryger [21]
\bf \textit{Sum and Difference Identities}
\\\\
tan(\alpha + \beta) = \cfrac{tan(\alpha)+ tan(\beta)}{1- tan(\alpha)tan(\beta)}
\qquad
tan(\alpha - \beta) = \cfrac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}\\\\
-------------------------------\\\\
\cfrac{tan(5x)-tan(2y)}{1+tan(5x)tan(2y)}\implies tan(5x-2y)
6 0
2 years ago
What is 1,015/12 as a mixed number and in simplest form?
ddd [48]
It would be 84 and 7/12
3 0
3 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
2 years ago
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