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dezoksy [38]
3 years ago
11

Suppose that you collect data for 15 samples of 30 units each, and find that on average, 2.5 percent of the products are defecti

ve. What are the UCL and LCL for this process? (Leave no cells blank - be certain to enter "0" wherever required. Do not round intermediate calculations. Round up negative LCL values to zero. Round your answers to 3 decimal places.)
Mathematics
1 answer:
Korvikt [17]3 years ago
8 0

Answer:

The  UCL  is  UCL  =  0.054

The LCL  is  LCL \approx 0

Step-by-step explanation:

From the question we are told that  

     The quantity of each sample is  n =  30

     The  average of defective products is  p  =  0.025

Now  the upper control limit [UCL] is  mathematically represented as

       

      UCL  = p +  3 \sqrt{\frac{p(1-p)}{n}  }

substituting values  

      UCL  = 0.025 +  3 \sqrt{\frac{0.025 (1-0.025)}{30}  }

      UCL  =  0.054

The  upper control limit (LCL) is mathematically represented as

       LCL  = p -  3 \sqrt{\frac{p(1-p)}{n}  }

substituting values  

      LCL  = 0.025 -  3 \sqrt{\frac{0.025 (1-0.025)}{30}  }

       LCL  = -0.004

        LCL \approx 0

       

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