Is -5 a solution to -9+5w<16

Mathematics

2 answers:

kozerog [31]4 years ago

4 0

-9 + 5w < 16
-9 + 5(-5) < 16
-9 + (-25) < 16
- 34 < 16

NO, -5 is not a solution to -9+5w<16

guapka [62]4 years ago

3 0

$-9+5w\ \textless \ 16$
$5w\ \textless \ 16+9$
$5w\ \textless \ 25$
$w\ \textless \ 5$

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Sergio [31]

Make denomenators the same
common denom is 2n²

multiply 3/2n by n/n
mulitply 1/n² by 2/2

we get
$\frac{3n}{2n^2}+\frac{2}{2n^2}=\frac{n-2}{2n^2}$
combine fractions
$\frac{3n+2}{2n^2}=\frac{n-2}{2n^2}$
multiply both sides by 2n²
2n+2=n-2
minus n both sides
n+2=-2
minus 2 both sides
n=-4

8 0

3 years ago

Points C and D divide the semicircle into three equal parts. Match the angles with their measures.

Tresset [83]

∠CAE = 120°
∠CAD = 60°
∠BAE = 180°
∠DEC = 30°

We start out with the fact that points C and D split the semicircle into 3 sections. This means that ∠BAC, ∠CAD and ∠DAE are all 60° (180/3 = 60).

Since it forms a straight line, ∠BAE is 180°.

Since it is formed by ∠CAD and ∠DAE, ∠CAE = 60+60 = 120°.

We know that an inscribed angle is 1/2 of the corresponding arc; since CD is 1/3 of the circle, it is 1/3(180) = 60; and this means that ∠DEC = 30°.

7 0

3 years ago

Read 2 more answers

PLEASE HELP I NEED THIS FAST

iren2701 [21]

Answer:

Step-by-step explanation: the x side is +5 and the y side is -15

3 0

3 years ago

The function f(x) = x^2 is reflected across the x-axis and a stretch factor of 4 is applied to create a second function, g(x). W

Anon25 [30]

C. The vertexes are the same. The functions' vertex (h,k) values were not altered, just a (stretch/compress).