When completing the square <span>x=9.12311 and </span><span>x=<span>0.876894</span></span>
Answer:
Step-by-step explanation:
At first,
Let start writing the squares of number 0 to 10,
0²=0
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
Now,
According to your question,
- The two numbers should be square numbers
- They should be greater than 1.
- Their sum should be 100.
Hence, your given conditions matches with the numbers 64 and 36.
Therefore, the numbers are 64 and 36.
- 64 and 36 are greater than 1.
- 64 is a square of 8 and 36 is the square of 6.
- 64+36=100
This is how i got the result, i hope it is correct!
<u>Answer:</u>
32 units
<u>Step-by-step explanation:</u>
We have a quadrilateral ABCD and we are given the following coordinates for these vertices:
A (-11,-6)
B (-3,0)
C (1,0)
D (1,-6)
AB = 
= 10 units
BC = 
= 4 units
CD = 
= 6 units
AD = 
= 12 units
Perimeter of ABCD = 
= 32 units
Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
