I believe is your answer
Because u plug in -2 to all x
F(x)= (-2)^2-9(-2)+2
F(x)=4+18+2
F(x)=24
Answer:
<h2>

</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
- inequality
- distribution
- PEMDAS
<h3>given:</h3>
<h3>to solve:</h3>
<h3>let's solve:</h3>






therefore,

Answer: 0=0
Step-by-step explanation:
First you want to solve for x
2x+y=−4
Step 1: Add -y to both sides.
2x + y + −y =−4+ −y
2x=−y−4
Step 2: Divide both sides by 2.
2x/2= -y-4/2
x=-1/2y-2
Then you want to plug in your answer for x into the equation so:
2(-1/2y-2)+y=-4
Step 1: Simplify both sides of the equation.
2(-1/2y-2)+y=-4
(2)(
−1/
2
y)+(2)(−2)+y(Distribute)
−y+−4+y=−4
(−y+y)+(−4)=−4(Combine Like Terms)
−4=−4
−4=−4
Step 2: Add 4 to both sides.
−4+4=−4+4
0=0.
Sorry if this wasn't the answer your looking for. If you need more help I suggest using Ma.th.Pa.pa calculator but with out the periods. Hope you have a good day :)
Answer:
Ikr >:(
Step-by-step explanation:
Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.