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Alborosie
3 years ago
8

How many yards are in 1 mile 600 ft

Mathematics
2 answers:
crimeas [40]3 years ago
6 0
A mile is a unit of length most commonly equivalent to 5280 feet (1760 yards, or about 1609 metres).
andrey2020 [161]3 years ago
3 0

Answer:1760 yards

Step-by-step explanation:brainly plzzzz

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What values of P and Q have exactly no solutions Px+40=Qx+20
Novosadov [1.4K]

You can not solve this because the values are different... If the values were both Px and Px or Qx and Qx you will be able to solve the problem but you can not according to the fact that they aren't the same letters. So therefore, this equation has no solution.


Hope this helped!!!

6 0
3 years ago
-40-8b=-6(1+7b) what’s the answer
Andre45 [30]

\text{Hey there!}

\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}

\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}

\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}

\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}

\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}

\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}

\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\ is:\boxed{\boxed{\mathsf{b=1}}}}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

8 0
3 years ago
Which expression is equivalent to (3−2^2) 5 ? 5−3^2 5−2^2 2^2−5 ​ 3^2−5
tamaranim1 [39]
Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5
8 0
3 years ago
(WORTH 95 POINTS) PLEASE HELP I CANNOT FIGURE IT OUT AND ITS SUPPOSED TO BE TURNED IN ALREADY!
yanalaym [24]

Hope this helped :3

:)

5 0
3 years ago
C= 2 7r; for r<br> Plzz help
Nutka1998 [239]

Answer:

C/27=r

Step-by-step explanation:

C= 2 7r

C \div 27= 2 7r \div 27

C/27=r

5 0
4 years ago
Read 2 more answers
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