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kupik [55]
3 years ago
8

What is the answer to this question or problem​

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

Number 16 is organ system

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The damage caused by electric shock depends on the current flowing through the body; 1 mA can be felt and 5 mA is painful. Above
Angelina_Jolie [31]

Answer: V_{min} = 110 V

Explanation:

Voltage is calculated by Ohm's Law:

V_{min} = i_{min} \cdot R_{dry}\\V_{min} = (0.001 A)\cdot(1.1 \times 10^5 \Omega)\\V_{min} = 110 V

3 0
3 years ago
Protons<br> Neutrons<br> Electrons<br> Location<br> Charge<br> Size
igor_vitrenko [27]
Protons are positive, and neutrons are negative, electrons are neutral. I’m not sure about the rest but I hope that helps for now
6 0
3 years ago
A car with a mass of 833 kg rounds an unbanked curve in the road at a speed of 28.0 m/s. If the
SSSSS [86.1K]
I had the same question

6 0
3 years ago
A child attempts to roll a ball up a long ramp and it slows as it goes up. If it is released at 2.5 m/s upward and accelerates d
valina [46]

Answer:

-0.7 m/s

Explanation:

Initial velocity (u)= 2.5 m/s

Acceleleration (a)= -0.8 m/s^2

Time taken (t) = 4  seconds

Hence,

v=u+at [1st Equation of motion]

v=2.5+-0.8*4

v=2.5-3.2

v=-0.7 m/s

Note that the negative sign indicates that the ball has changed direction and rolls downwards with gravity

8 0
3 years ago
A sample of copper with a mass of 1.80 kg, initially at a temperature of 150.0°C, is in a well-insulated container. Water at a t
user100 [1]

Answer:

the mass of water is 0.3 Kg

Explanation:

since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:

Q water + Q copper = Q surroundings =0 (insulated)

Q water = - Q copper

since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature

and denoting w as water and co as copper :

m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) =  m co * c co * (T co - Ti eq)

m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]

We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C

if we assume that both specific heats do not change during the process (or the change is insignificant)

m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]

m w= 1.80 kg *  0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))

m w= 0.3 kg

7 0
4 years ago
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