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3 years ago

Which of these experiments would make use of quantitative data?

2 answers:

Klio2033 [76]3 years ago

6 0

An experiment that would make use of quantitative data would be A. A study of the different amounts of time it takes water to evaporate completely.

denis23 [38]3 years ago

5 0

Answer;

A study of the different amounts of time it takes water to evaporate completely

Explanation;

-Quatitative data are anything that can be expressed as a number, or quantified. Examples of quantitative data are scores on achievement tests,number of hours of study, or weight of a subject. These data may be represented by ordinal, interval or ratio scales and lend themselves to most statistical manipulation.

-Qualitative data on the other hand, cannot be expressed as a number. Data that represent nominal scales such as gender, social economic status, religious preference are usually considered to be qualitative data.

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Help quick<br> ................

sattari [20]

The answer is B because there is a total of 10N to the right and 5 to the left, 10-5=5

4 0

3 years ago

How long does it take a plane that is traveling at 350 km/h to travel 1750 km?

olga2289 [7]

S=d/t
T=d/s
= 1750/350
= 5 hours

3 0

3 years ago

What is a real-life example of destructive interference of light?

34kurt

Destructive Interference. An example of destructive interference is noise canceling headphones. Noise canceling headphones work by using a microphone to pick up the frequencies of incoming waves. The headphone then sends out a wave that is the exact opposite, canceling out the sound.

6 0

3 years ago

Force X has a magnitude of 1260 pounds, and Force Y has a magnitude of 1530 pounds. They act on a single point at an angle of 4

weeeeeb [17]

Answer:

Fe= 2579.68 P

α= 24.8°

Explanation:

Look at the attached graphic

we take the forces acting on the x-y plane and applied at the origin of coordinates

FX = 1260 P , horizontal (-x)

FY = 1530 P , forming 45° with positive x axis

x-y components FY

FYx= - 1530*cos(45)° = - 1081.87 P

FYy= - 1530*sin(45)° = - 1081.87 P

Calculation of the components of net force (Fn)

Fnx= FX + FYx

Fnx= -1260 P -1081.87 P

Fnx= -2341.87 P

Fny=FYy

Fny= -1081.87 P

Calculation of the components of equilibrant force (Fe)

the x-y components of the equilibrant force are equal in magnitude but in the opposite direction to the net force components:

Fnx= -2341.87 P, then, Fex= +2341.87 P

Fny= -1081.87 P P, then, Fex= +1081.87 P

Magnitude of the equilibrant (Fe)

$F_{n} = \sqrt{(F_{nx})^{2} +(F_{ny})^{2} }$

$F_{e} =\sqrt{(2341.87)^{2}+(1081.87)^{2} }$

Fe= 2579.68 P

Calculation of the direction of equilibrant force (α)

$\alpha =tan^{-1} (\frac{F_{ny} }{F_{nx} } )$

$\alpha =tan^{-1} (\frac{1081.87 }{2341.87} )$

α= 24.8°

Look at the attached graphic

6 0

3 years ago

In a simple electric circuit, a 110-volt electric heater

Readme [11.4K]

Answer: 55 ohms

Explanation:

Given that,

Voltage of heater (v) = 110-volt

Current drawn by heater (I) = 2.0 amperes

resistance of the heater (r) = ?

Since voltage, current and resistance are involved, apply the formula for ohms law.

Voltage = current x resistance

i.e v = ir

where r = v / i

r = 110 volts / 2.0 A

r = 55 ohms

Thus, the resistance of the heater is 55 ohms

6 0

3 years ago