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Arada [10]
3 years ago
5

A catapult is malfunctioning and not throwing objects in the intended manner. The builders have modeled the path of the objects

thrown by using the following parametric equations. rewrite the parametric equations by eliminating the parameter.
x(t)=2t-1
y(t)= square root of t; t> or equal to 0
Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Answer:

The equation is y ^ 2 = \frac{x + 1}{2}

Step-by-step explanation:

The parameter that we have is t. We want to eliminate this parameter in both equations, therefore in the first equation we solve for t and in the second equation we solve for the variable t.

We have:

x = 2t-1\\\\x + 1 = 2t\\\\t = \frac{x + 1}{2}

Now we solve the other equation for t.

y= \sqrt{t}

y ^ 2 = t    <em> because</em>   t> 0

As t = y ^ 2 and also t = \frac{x + 1}{2}

Then:

y ^ 2 = \frac{x + 1}{2}

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2 1/5 × 5/6<br> (its a fraction) <br> PLSSS i need it now its a test
Soloha48 [4]

Answer:

\frac{11}{6} \ \ or \ 1\frac{5}{6}

Step-by-step explanation:

2\frac{1}{5} \times \frac{5}{6} \\\\ = \frac{11}{5} \times \frac{5}{6} \\\\=\frac{11}{6}\\\\=1 \frac{5}{6}

6 0
2 years ago
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Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

c. 6x + y = -52    

or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

3 0
3 years ago
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The front of a box is a square with an area of 175 square units. What would be the best represents S, the length of the edge of
alexira [117]

Answer:

  13.2

Step-by-step explanation:

√175 ≈ 13.2 . . . units

The area of a square is the square of the edge length. Hence, the edge length is the square root of the area.

3 0
3 years ago
Jeremiah is working on a model bridge. He needs to create triangular components, and he plans to use toothpicks. He finds three
icang [17]

Answer: No

Step-by-step explanation:

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Now let's test the given parameters if they obey this theorem

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Therefore he won't be able to create the triangular component with these toothpicks without modifying any of the lengths

3 0
3 years ago
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Galina-37 [17]

Answer

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8 0
3 years ago
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