Answer: The first outcome shall be 0.33 or 33%.
The second outcome would be 0.5 or 50%
Step-by-step explanation: The bag contains exactly one yellow, one red and one green marble. So when he draws the first marble the sample space shall be the total possible outcomes, which is three, since he has three (3) marbles altogether. When he draws the first time without looking, all three marbles have an equal probability of being picked which can be derived thus;
P(Red) = Number of required possibilities/Number of all possibilities
P(Red) = 1/3
P(Red) = 0.33
Note that there is only one marble of each color which means P(Yellow) and P(Green) is also 0.33 respectively.
After choosing the first marble, without replacing the first one he now chooses another marble. The sample size would have reduced to 2 (since one marble has been drawn). Hence, the outcome when he draw a second marble can be calculated as follows;
P(Red) = Number of required outcomes/Number of possible outcomes
P(Red) = 1/2
P(Red) = 0.5
what is the question? if u give the question , I might help and edit this :)
Add all parts shared 2+3+7=12
Therefore 1 part is 176,496÷12= $14,708.
This means:
Luc has 2 parts: $14,708×2=$29,416
Deborah has 3 parts: $14,708×3=$44,124
Melanie has 7 parts: $14,708×7=$102,956
To check add all values together. If it makes the total amount, then the share is correct. 29,416+44,124+102,956=$176,496
Answer:
- The smallest area the field could be is 6,400 m²
- The largest area the field could be is 8,250 m²
Step-by-step explanation:
Given;
smallest possible length of the international soccer field, L₀ = 100 m
smallest possible breadth of the international soccer field, B₀ = 64 m
Largest possible length of the international soccer field, L₁ = 110 m
Largest possible breadth of the international soccer field, B₁ = 75 m
Area of a rectangle is given by;
A = L x B
The smallest area the field could be is calculated as;
A₀ = L₀ x B₀
A₀ = 100 m x 64 m
A₀ = 6,400 m²
The largest area the field could be is calculated as;
A₁ = L₁ x B₁
A₁ = 110 m x 75 m
A₁ = 8,250 m²
<span>The assumption that YZ is perpendicular bisector of AX is not enough to show hat YXZ equals YAZ is false</span>
