Help if your good at maths
2 answers:
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So... the motorboat went up the river, at a rate of 10km/hr
against the river current, let's say... the river has a current rate,
of "r", so the boat, once we subtract "r" from 10, the boat
wasn't really going 10km per hr, it was going slower, because
the river was slowing it down, so the motorboat rate was 10-r
it went up some distance, say "d", for 45 mins
broke down
backslid for 3hrs, back to port
notice, it went up for 45mins, distance "d"
broke down, then backslid back to quarters
ahemm..... the distance it backslid, HAS to be
the same distance "d"
since the boat went, stopped, and came back,
same distance "d"
took 3hrs for that though.... or 180 minutes
so... let's take a peekd at the d = rt
distance = rate * time
solve for "r"
against the river current, let's say... the river has a current rate,
of "r", so the boat, once we subtract "r" from 10, the boat
wasn't really going 10km per hr, it was going slower, because
the river was slowing it down, so the motorboat rate was 10-r
it went up some distance, say "d", for 45 mins
broke down
backslid for 3hrs, back to port
notice, it went up for 45mins, distance "d"
broke down, then backslid back to quarters
ahemm..... the distance it backslid, HAS to be
the same distance "d"
since the boat went, stopped, and came back,
same distance "d"
took 3hrs for that though.... or 180 minutes
so... let's take a peekd at the d = rt
distance = rate * time
solve for "r"