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xz_007 [3.2K]
3 years ago
7

A dart is thrown at the board shown. it hits the board at a random point. find the probability that it will land in an unshaded

region. round to the nearest percent.
A. 25%
B.67%
C.75%
D.33%

Mathematics
2 answers:
aliina [53]3 years ago
8 0

Answer:

The correct option is C. The probability that it will land in an unshaded region is 75%.

Step-by-step explanation:

The given figure it square, which is divide into 4 equal square. Out of these two squares are half shaded.

If these 4 small square are divided in two equal parts, then total number of parts are 8. Out of 2 parts are shaded.

The probability that it will land in an unshaded region is

P=\frac{\text{Unshaded parts}}{\text{Total number of parts}}\times 100

P=\frac{6}{8}\times 100

P=\frac{3}{4}\times 100

P=75\%

Therefore probability that it will land in an unshaded region is 75%. Option C is correct.

kupik [55]3 years ago
6 0

Answer:

d

Step-by-step explanation:


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madam [21]

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y = ax + b

I see already the result (y = x/10 × 1/6), but let's go in formally.

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