ohh noo the question..
it an mf whole question paper
Step-by-step explanation:
youre done sis
Answer:
x = 2.5
Step-by-step explanation:
The arc length x is calculated as
x = circumference of circle × fraction of circle
= 2πr ×
( cancel 2π on numerator/ denominator )
x = 1 × 2.5 = 2.5
Answer:
The probability that a voter chosen at random is in the 18 to 20 years old age range is = 4.2/ 134.8= 0.0311572
Step-by-step explanation:
We can find the probability by simply dividing the frequency of the ages range of 18-20 by the total frequency.
Ages Frequency
18 to 20 4.2
21 to 24 7.8
25 to 34 20.8
35 to 44 23.7
45 to 64 50.1
<u>65 and over 28.2</u>
<u>∑ 134.8</u>
The probability of an event is given by the occurrence of an event by the total occurrences .
So
Here the occurrence of ages 18-20 is given by 4.2
and the total frequency is 134.8
The probability that a voter chosen at random is in the 18 to 20 years old age range is = 4.2/ 134.8= 0.0311572
Let's assume
number of birds with 2 wings is x
number of birds with 4 wings is y
A nature museum has 2008 specimens of early birds
so,

Total of wings of 2 wings bird =2x
Total of wings of 4 wings bird =4y
The specimens have a total of 4384 wings
so, we get

we can divide both sides by 2

so, we get system of equations as


we can solve for x and y
We can subtract both equations





so,
number of birds with 2 wings is 1824
number of birds with 4 wings is 184.............Answer
So one way is to have a number close to 7
14.00000000000000000000001/2
21.00000000000000000001/3
28.000001/4
etc