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11Alexandr11 [23.1K]
3 years ago
14

What is the equation of the line that passes through the point (3,-5)(3,−5) and has a slope of 0?

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

y=x-5

Step-by-step explanation:

y=mx+b

-5=0(3)+b

0(3)-5=b

-5=b

y=x-5

Correct me if im wrong

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The angle 01 is located in Quadrant III, and cos(01) = -30/13
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Answer:

<h2>sin(01) = -32.70/13</h2>

Step-by-step explanation:

Given cos(01) = -30/13 where angle 01 is located in quadrant III. In the third quadrant, both cos and sin are negative. only tan is positive.

To calculate sin(01), we will apply the trigonometry expression as shown below;

cos(01) = -30/13

According to SOH CAH TOA;

cos(01) = adjacent/hypotenuse = -30/13

sin(01) = opposite/ hypotenuse

To get the hypotenuse, we will use the pythagoras theorem

hyp^{2}=opp^{2}+adj^{2}   \\opp^{2}=  hyp^{2}-adj^{2}\\opp^{2}= 13^{2} -(-30^{2} )\\opp^{2} = 169+900\\opp^{2}=1069\\opp = \sqrt{1069} \\opp = 32.70\\

sin(01) = 32.70/13

Since sin is also negaitve in the third quadrant, the value of

sin(01) = -32.70/13

01 = cos^{-1}- 30/13

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3 years ago
300 has how many<br> 2/3 in it?
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