Answer:
3 m
Step-by-step explanation:

Given:
- volume = 10 m³
- Area of base = 10 m²




The duration of the class is uniformly distributed with a minimum of 50.0 minutes and a maximum of 52.0 minutes. This means the random variable for class duration

has density function
![f_X(x)=\begin{cases}\dfrac1{52.0-50.0}=\dfrac12&\text{for }50.0\le x\le52.0\\[1ex]0&\text{otherwise}\end{cases}](https://tex.z-dn.net/?f=f_X%28x%29%3D%5Cbegin%7Bcases%7D%5Cdfrac1%7B52.0-50.0%7D%3D%5Cdfrac12%26%5Ctext%7Bfor%20%7D50.0%5Cle%20x%5Cle52.0%5C%5C%5B1ex%5D0%26%5Ctext%7Botherwise%7D%5Cend%7Bcases%7D)
You're looking for the probability that the class runs less than 51.5 minutes, or

, which is given by the integral
Answer:
120 planters.
Step-by-step explanation:
given each planter can hold (1/8) of soil
i.e:
1/8 bag -------> can fill 1 planter
1 bag -----------> can fill 1 / (1/8) = 8 planters
15 bags ---------> can fill 8 planters per bag x 15 bags = 120 planters.
Answer:
14 installatons
42 service calls
Step-by-step explanation:
Let x = no. of new installations
y = no. of service calls
(1) x + y = 56 (2) 450x + 75y = 9450
y = 56 - x 450x + 75(56 - x) = 9450
450x + 4200 - 75x = 9450
375x = 5250
x = 14 installatons
y = 56 - 14 = 42 service calls
Answer:
reeee whenever it was happy bday ily by :)