It would be the second answer. He starts with 2/3 cup, then take out 2 1/6 cup amounts, which make 2/6 cup. Since he's taking it out, you would subtract it from the original value. So you would get 2/3 cup minus 2/6 cup and to make the denominators equal you would multiply 2/3 cup by 2, so you would have 4/6 cup minus 2/6 cup which equals 2/6 cup.
Answer:
5
Step-by-step explanation:
The 32 that have blue and green ribbons include the 16 that have all three, so there are only 32 -16 = 16 that have only blue and green ribbons.
The 31 that have green and white ribbons likewise include the 16 with all three, so there are only 31 -16 = 15 that have only green and white ribbons.
The 38 that have blue and white ribbons include the 16 with all three, so there are only 38 -16 = 22 that have only green and white ribbons.
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If we add the numbers of blue, green, and white ribbons, we are counting twice the numbers that have 2 ribbons, and 3 times the numbers that have 3 ribbons. We want to count each kind of ribbon-holder only once. Hence the number of individual dogs with any number of ribbons is only ...
62 +55 +63 -(16 +15 +22) -2(16) = 95
Of the 100 dogs, 95 have ribbons, so 5 dogs have not learned any tricks.
I interpret the first number to be 89.24, so 84 and 24 hundredths.
The difference would be by how many numbers they differ, so we subtract the smaller from the bigger:
89.24-17=12.24
this would be their difference!
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