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leonid [27]
3 years ago
8

Solve for x. x= ____

Mathematics
1 answer:
Alika [10]3 years ago
6 0
Maybe 193*? ((A^2)+(B^2))=C^2 so, (160^2)+(180^2)=37264....the square root of 37264 is rounded off to 193
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Evan's rectangular lawn measures 8 yards by 10 yards. He planted a hedge
bezimeni [28]

Answer:

Length of rectangular lawn =72 meters

Breadth of rectangular lawn =18 meters

Perimeter of rectangle =2(Length+Breadth)

So, Perimeter of rectangle =2(72+18)=2(90)=180 meters

If three shrubs can be planted in a meter of hedge.

Then, Number of shrubs planted in whole perimeter will be=3×180=540

Step-by-step explanation:

8 0
2 years ago
Explain a strategy u could use to compare 2/6 and 5/8.
Schach [20]
Try to get the fractions with same denominators. Use the LCD system to find equal factors to a common denominator. Then just simply compare it. 

*Note: Larger fraction is the greater numerator.*

Hoped this helped.

~Bob Ross® 
6 0
3 years ago
Write the equation of the line that passes through the points (- 5, 1) and (2, 0) . Put your answer in fully reduced slope inter
Doss [256]

Answer:

y=-1/7x + 12/7

Step-by-step explanation:

Start by finding the slope

m=(1-0)/(-5-2)

m=-1/7

next plug the slope and the point (-5,1) into point slope formula

y-y1=m(x-x1)

y1=1

x1= -5

m=-1/7

y- 1 = -1/7(x - -5)

y-1=-1/7(x+5)

Distribute -1/7 first

y- 1=-1/7x + 5/7

Add 1 on both sides, but since its a fraction add 7/7

y=-1/7x + (5/7+7/7)

y=-1/7x+12/7

3 0
3 years ago
Which answers choice shows that the set of irrational numbers is not closed under addition?
babunello [35]
Problably A !!!!!!!!!!!
7 0
3 years ago
Read 2 more answers
Which of the following statements must be true about the polynomial function f(x)? If 1+ the sqrt of 13 is a root of f(x), then
son4ous [18]

The correct answer is: if 1 + 13i is a root of f(x), then 1 - 13i is also a root of f(x).


In fact, every polynomial has real and/or complex solutions. If all solutions are real, we're good. But if not all of them are real, then the complex ones come in couple of conjugate solutions. Since 1 + 13i and 1 - 13i are conjugate complex numbers, if one of them is a solution, the other must be as well.

7 0
3 years ago
Read 2 more answers
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