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victus00 [196]
2 years ago
7

$5000 is invested at 3% interest. How much money must be invested at 5% interest so that the total interest from the two investm

ents is $275 after one year?
Mathematics
1 answer:
SpyIntel [72]2 years ago
7 0

5000x3/100=150

275-150=125

125x100/5=2500

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Multiplying two complex numbers involves ______.
Alenkasestr [34]

Answer:

Multiplying a complex number by a real number

(x + yi) u = xu + yu i. In other words, you just multiply both parts of the complex number by the real number. For example, 2 times 3 + i is just 6 + 2i. Geometrically, when you double a complex number, just double the distance from the origin, 0.

binomial methods

Complex numbers use binomial methods of multiplication because unlike real numbers, imaginary numbers have two components.

So probably A. I sorry, but I need more information. Hope this helps

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Intersection point of Y=logx and y=1/2log(x+1)
GalinKa [24]

Answer:

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

The Problem:

What is the intersection point of y=\log(x) and y=\frac{1}{2}\log(x+1)?

Step-by-step explanation:

To find the intersection of y=\log(x) and y=\frac{1}{2}\log(x+1), we will need to find when they have a common point; when their x and y are the same.

Let's start with setting the y's equal to find those x's for which the y's are the same.

\log(x)=\frac{1}{2}\log(x+1)

By power rule:

\log(x)=\log((x+1)^\frac{1}{2})

Since \log(u)=\log(v) implies u=v:

x=(x+1)^\frac{1}{2}

Squaring both sides to get rid of the fraction exponent:

x^2=x+1

This is a quadratic equation.

Subtract (x+1) on both sides:

x^2-(x+1)=0

x^2-x-1=0

Comparing this to ax^2+bx+c=0 we see the following:

a=1

b=-1

c=-1

Let's plug them into the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}

x=\frac{1 \pm \sqrt{1+4}}{2}

x=\frac{1 \pm \sqrt{5}}{2}

So we have the solutions to the quadratic equation are:

x=\frac{1+\sqrt{5}}{2} or x=\frac{1-\sqrt{5}}{2}.

The second solution definitely gives at least one of the logarithm equation problems.

Example: \log(x) has problems when x \le 0 and so the second solution is a problem.

So the x where the equations intersect is at x=\frac{1+\sqrt{5}}{2}.

Let's find the y-coordinate.

You may use either equation.

I choose y=\log(x).

y=\log(\frac{1+\sqrt{5}}{2})

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

6 0
2 years ago
21. What must be added to -9 to have a sum of 20?
Inga [223]

Answer:

21C

22D

23B

24C

25A

Step-by-step explanation:

7 0
2 years ago
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Simon has a scale model of the Concorde airplane. The actual length of the Concorde is approximately 200 feet. If the ratio of t
Verizon [17]
The answer is:  "40 cm " .
_________________________________________________________
<u>Note</u>:
_________________________________________________________

\frac{200 ft }{ (x) cm} = \frac{5}{1}  ;

Solve for "x" (in "cm" ) ; 


→  5x = 200 * 1 ; 

→  5x = 200 ; 

Divide each side of the equation by "5" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

→  5x / 5 = 200 / 5 ; 

to get:

→  x = 40 .
___________________________________________________________
The answer is:  " 40 cm " .
___________________________________________________________
6 0
3 years ago
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If i only have 1/3 cups how many 1/3cups do i need to make a cup? answer asap!?​
Mrac [35]

Answer:

2 1/3 ssssssssssssddddss

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3 years ago
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