Question

What is the perimeter of triangle ABC ?

Answer 1

Answer:

$9+\sqrt{41}$

Step-by-step explanation:

From C-A, it goes from y=1 to y=5, so that 4 units

From A-B, it goes from x = -1 to x = 4, that is 5 units

Now, to find distance from B to C, we need to use the distance formula:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Where the variables are the respective points of B and C,

B (4,5) & C(-1,1)

So x_1 =4, y_1=5, x_2=-1, y_2=1

Plugging into the formula we get:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\D=\sqrt{(1-5)^2+(-1-4)^2}\\D=\sqrt{16+25}\\ D=\sqrt{41}$

Summing it all (perimeter is sum of 3 sides):

Distance = $4+5+\sqrt{41}\\ =9+\sqrt{41}$

3rd answer choice is right.