(a^2-4a+6)+(3a^2+13a-1) finding the sum of the difference

Mathematics

1 answer:

andreev551 [17]4 years ago

5 0

(a² - 4a + 6) + (3a² + 13 - 1)
= a² + 3a² - 4a + 13a + 6 - 1
= 4a² + 9a + 5

Hope this helps! :)

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