Given:
A line passes through (1,-2) and is perpendicular to .
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
(x - 10)² + (y + 9)² = 20
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
The radius is the distance from the centre to a point on the circle
To calculate r use the distance formula
r = √(x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (10, - 9) and (x₂, y₂ ) = (12, - 13)
r =
= =
, hence
(x - 10)² + (y - (- 9))² = ()², that is
(x - 10)² + (y + 9)² = 20