Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
Answer:
2, and 5
Step-by-step explanation:
. V = B( h )
. V = (pi) (r squared) (h)
Answer:
4.9 units
Step-by-step explanation:
Distance between 2 points= sqrt [(x-x)^2 + (y-y)^2
A= -4,2) and B= (1,4)
d = sqrt[(-4-1)^2 + (2-4)^2]
= sqrt (25+4)
= sqrt29
= 4.9 units
-48 plugging in everything and using PEMDAS it should be -48
Answer:
See below
Step-by-step explanation:
a = 15 sqrt 2 sin 45
= 15 sqrt 2 * sqrt( 2 ) /2 = 15 * 2 /2 = 15
sin 60 = a/c
sqrt(3)/2 = 15/c
c = 15 / ( sqrt(3)/2) = 30 / sqrt 3 = 30 sqrt 3 /3 = 10 sqrt 3
