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kirill115 [55]
3 years ago
5

The data set below has 7 values find the mean absolute deviation for the data set if necessary round your answer to the nearest

hundredth 16,10,17,12,79,13
Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0
Hello there,

Even though there is only 6 we can use the 6 there.
 
So the mean is all the data values added up by how many values there are in this case there are 6.

So that means 16 + 10 + 17 + 12 + 79 + 13 = 147

And because there are 6 values, you divide 147 by 6. 

Therefore getting 147/6 = 24.5

Hope this helps you!
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dangina [55]

Answer: 6 3/4

Step-by-step explanation:

 1. Use proportion:

8:4.5=24:x

8x=24*4.5

x=3*4.5

x=13.5

2. Use proportion

8:4.5=4:x

x8=18

x=18/8

x=9/4

x=2.25

3. For 24 people you need 13,5

for 12 people you need :

24:13.5=12:x

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What is the quotient ? -4/2 divided by 2
professor190 [17]

Answer:

\frac{-\frac{4}{2} }{2} =-\frac{4}{2} *\frac{1}{2} =-\frac{4}{4} =-1

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The height of a cone is twice the radius of its base. A cone has a height of 2 x and a radius of x. What expression represents t
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Answer:

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Step-by-step explanation:

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V=\pi r^{2} \frac{h}{4} \\V=\pi *x^{2} *\frac{1}{2} x\\V=\frac{1}{2} \pi x^{3}

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A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

80P+40Q=48800

Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

\displaystyle R=Q\cdot \frac{1120-Q}{2}

\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

R=\$156,800

And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
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