Question

(2y^2+9y+4)+(-3y^2-3y)

Answer 1

Solve for y:
-y^2 + 6 y + 4 = 0

Multiply both sides by -1:
y^2 - 6 y - 4 = 0

Add 4 to both sides:
y^2 - 6 y = 4

Add 9 to both sides:
y^2 - 6 y + 9 = 13

Write the left hand side as a square:
(y - 3)^2 = 13

Take the square root of both sides:
y - 3 = sqrt(13) or y - 3 = -sqrt(13)

Add 3 to both sides:
y = 3 + sqrt(13) or y - 3 = -sqrt(13)

Add 3 to both sides:

Answer:  y = 3 + sqrt(13) or y = 3 - sqrt(13)