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Scorpion4ik [409]
3 years ago
6

Which of the following statements is true? A. Vertical angles are always complementary. B. Vertical angles are always supplement

ary. C. Vertical angles are always equal in measure. D. Vertical angles sometimes have different measures.
Mathematics
2 answers:
denpristay [2]3 years ago
5 0
Vertical angles always equal in measure
Savatey [412]3 years ago
4 0

The correct statement about vertical angles is that they are always equal in measure. This also implies they are congruent. Therefore, the correct answer is C.

For example, if a vertical angle measures 140 degrees, it means the other angle will also measure 140 degrees.

<h2>Further Explanation</h2>

Vertical angles are always equal in measure, they are very special angle and they are congruent to one another.

Vertical angles are non-adjacent angles and they are formed when 2 lines intersect. In vertical angles, all the pairs of the angles are opposite each other.

The angles that opposite another are called supplementary and their sum in total is 180 degrees.

However, there are four different types of angles and these include

  1. Vertical angle
  2. Complementary angle
  3. Supplementary angle
  4. Adjacent angle

Complementary angle: they are 2 angles that measure 90 degrees, that is they form a right angle

Supplementary angle: they are 2 angles that measure 180 degree

Adjacent angle: they are 2 angles that have common vertex (corner point) and a common side. Also, adjacent angles don’t overlap. When 2 angles have a corner point and a common side, it implies that the 2 angles shared the vertex point and the side.

Therefore, the correct statement about vertical angles is that they are always equal in measure (they are congruent)

LEARN MORE:

  • Which of the following statements is true?  brainly.com/question/10236745
  • Which of the following statements is true? brainly.com/question/1043940

KEYWORDS:

  • congruent
  • vertical angles
  • supplementary angles
  • different measures
  • complementary angles
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notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

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-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

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Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

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So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

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now we can factor out x from the first expression and -7 from the second

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The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

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In our case, a=3x and b=2

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(3x-2)^2

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posledela

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