Answer:
$93.75
Step-by-step explanation:
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:
Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:
Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1
Hey there!
To start, the mean of the answer is also known as the average value of a set of numbers. This is calculated by dividing the sum of the set by the total amount of numbers.
In this case the sum of all the numbers is 13 + 6 + 8 + 6 + 15 which is equal to 48.
Now, divide 48 by the total number of numbers in the set: 48/5 = 9.6
Your final answer should be 9.6, or you can leave it in fraction form as 48/5.
Hope this helps!
Y= -3x +4
So from the equation we can tell that m is 3 .
(0,-1)
(x, y)
0 = x
-1 = y
M = 3
Y = mx+ c
Just insert it
-1 = 3(0) + c
-1 = c
So thts mean the answe is y = 3x-1
Answer:
m > 3 for 2 solutions.
m = 3 for one solution.
Step-by-step explanation:
mx^2 - 2mx + 3 = 0
For 2 solutions the discriminant b^2 - 4ac > 0 so we have
(-2m)^2 - 4*m* 3 > 0
4m^2 - 12m > 0
4(m^2 - 3m) > 0
m^2 - 3m > 0
m(m - 3) > 0
m > 3 - this is the result for 2 solutions.
For one solution the discriminant = 0
so m(m - 3) = 0
and m = 3 for 1 solution.
