All categories

3 years ago

Describe the range of a square root function

1 answer:

5 0

It really depends on the function.

If it's:
sqrt(x^3 - 3x + 47), or something similar,
The RANGE will be ALL REAL NUMBERS.

Most of the time the range of a square root function (provided all of the function is inside the square root) will be all reals. This is because all positive integers have a positive and negative square root.

You might be interested in

Greta wants to make 5 pounds of a nut mix using peanuts and cashews. Her budget requires the mixture to cost her $6 per pound. P

Vinil7 [7]

Answer:

3 pounds of peanuts and 2 pounds of cashews

Step-by-step explanation:

Let x be the pounds of peanuts and y be the pounds of cashews

Greta wants to make 5 pounds of a nut mix using peanuts and cashews.

So, $x+y=5$ ----- A

Cost of 1 pound of peanuts = $4

Cost of x pounds of peanuts = 4x

Cost of 1 pound of cashews = $9

Cost of y pounds of cashews = 9y

Her budget requires the mixture to cost her $6 per pound

So, cost of mixture of x pounds of peanuts and y pounds of cashews is 6(x+y)

So, $4x+9y=6(x+y)$ --- B

Plot A and B

$x+y=5$ ---Blue

$4x+9x=6(x+y)$ ---Green

Refer the attached figure

Intersection point = (x,y)=(3,2)

Hence she should use 3 pounds of peanuts and 2 pounds of cashews

6 0

3 years ago

11111111111111111111111

Nat2105 [25]

Answer:

1) Zero based on (-16·t - 2) is t = -1/8 second

2) Zero based on (t - 1) is t = 1 second

Step-by-step explanation:

The given functions representing the height of the beach ball the child throws as a function of time are;

y = (-16·t - 2)·(t - 1) and y = -16·t² + 14·t + 2

We note that (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

Therefore, the function representing the height of the beachball, 'y', is y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The zeros of a function are the values of the variables, 'x', of the function that makes the value of the function, f(x), equal to zero

In the function of the question, we have;

y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The above equation can be written as follows;

y = (-16·t - 2) × (t - 1)

Therefore, 'y' equals zero when either (-16·t - 2) = 0 or (t - 1) = 0

1) The zero based on (-16·t - 2) = 0, is given as follows;

(-16·t - 2) = 0

∴ t = 2/(-16) = -1/8

t = -1/8 second

The zero based on (-16·t - 2) is t = -1/8 second

2) The zero based on (t - 1) = 0, is given as follows;

(t - 1) = 0

∴ t = 1 second

The zero based on (t - 1) is t = 1 second

4 0

3 years ago

What is the circumference of a 45 m circle

Kobotan [32]

to solve circumference of a circle is diameter times pi.
C=141.3 cm

3 0

3 years ago

Read 2 more answers

Given that a, b, and c are non-zero real numbers and a + b ≠ 0, solve for x. ax + bx - c = 0

klemol [59]

The answer to the selected problem is: that is a linear equation.

4 0

3 years ago

PLEASE ANSWER ASASP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!

kvasek [131]

Answer:

bndflvb

Step-by-step explanation:

5 0

3 years ago