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Svetlanka [38]
3 years ago
5

Describe the range of a square root function

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0
<span>It really depends on the function. 

If it's: 
sqrt(x^3 - 3x + 47), or something similar, 
The RANGE will be ALL REAL NUMBERS. 

Most of the time the range of a square root function (provided all of the function is inside the square root) will be all reals. This is because all positive integers have a positive and negative square root. </span>
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HELP PLEASE! (Look at the picture!!!!)
Marianna [84]

Answer:

8

Step-by-step explanation:

The radius is part of a 3-4-5 special right triangle.

The diameter is two times the radius, so 4*2=

<em>I hope this helps! :)</em>

7 0
2 years ago
what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?
seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

0

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2

We we able to cancel out that factor that was giving us x=-4 is a zero.  

Therefore there is a hole at x=-4.

7 0
3 years ago
Find the value of x in the following quadrilateral
vlabodo [156]

Answer:

The answer is 63.31

Step-by-step explanation:

2x - 5 + 3x - 42 + x +  \frac{3}{7} x = 360 \\  \frac{45}{7} x = 360 + 47 \\ x = 63.31

6 0
3 years ago
How can you tell if 1245 is divisible by3 and by 0?
laiz [17]
First check if the first two digits are divisible by 3 (45 / 3 = 15 So yes it is) And then if the first two are divisible by 3, then check if the next two are divisible by three, (12 / 3 = 4 ) Yes, so if both are, then yes the answer is divisible by three.
3 0
3 years ago
Read 2 more answers
A manufacturer knows that on average 20% of the electric toasters produced require repairs within 1 year after they are sold. Wh
Effectus [21]

Answer:

(a) The value of <em>x</em> is 5.

(b) The value of <em>y</em> is 15.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of electric toasters produced that require repairs within 1 year.

And the let the random variable <em>Y</em> represent the number of electric toasters produced that does not require repairs within 1 year.

The probability of the random variables are:

P (X) = 0.20

P (Y) = 1 - P (X) = 1 - 0.20 = 0.80

The event that a randomly selected electric toaster requires repair is independent of the other electric toasters.

A random sample of <em>n</em> = 20 toasters are selected.

The random variable <em>X</em> and <em>Y</em> thus, follows binomial distribution.

The probability mass function of <em>X</em> and <em>Y</em> are:

P(X=x)={20\choose x}(0.20)^{x}(1-0.20)^{20-x}

P(Y=y)={20\choose y}(0.20)^{20-y}(1-0.20)^{y}

(a)

Compute the value of <em>x</em> such that P (X ≥ x) < 0.50:

P (X \geq x) < 0.50\\\\1-P(X\leq x-1)

Use the Binomial table for <em>n</em> = 20 and <em>p</em> = 0.20.

0.411=\sum\limits^{3}_{x=0}[b(x,20,0.20)]

The least value of <em>x</em> that satisfies the inequality P (X ≥ x) < 0.50 is:

<em>x</em> - 1 = 4

<em>x</em> = 5

Thus, the value of <em>x</em> is 5.

(b)

Compute the value of <em>y</em> such that P (Y ≥ y) > 0.80:

P (Y \geq y) >0.80\\\\P(Y\leq 20-y)>0.80\\\\P(Y\leq 20-y)>0.80\\\\\sum\limits^{20-y}_{y=0}[{20\choose y}(0.20)^{20-y}(1-0.20)^{y}]>0.80

Use the Binomial table for <em>n</em> = 20 and <em>p</em> = 0.20.

0.630=\sum\limits^{4}_{y=0}[b(y,20,0.20)]

The least value of <em>y</em> that satisfies the inequality P (Y ≥ y) > 0.80 is:

20 <em>- y</em> = 5

<em>y</em> = 15

Thus, the value of <em>y</em> is 15.

3 0
2 years ago
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