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VashaNatasha [74]
3 years ago
10

title="\frac{3}{4} q^{2}+7-\frac{1}{2} q^{2}" alt="\frac{3}{4} q^{2}+7-\frac{1}{2} q^{2}" align="absmiddle" class="latex-formula">

Simplify this quesstion
Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0
1/4q^2 +7
Hope this helps :)
Molodets [167]3 years ago
8 0

Answer:

The correct answer is,

\frac{ {q}^{2} }{4}  + 7

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<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

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For the considered case, it is given that:

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The count of the sections the class should label as "Chocolate Ice Cream" should be such that spinner getting "Chocolate Ice Cream" as option should have the probability as 0.3

Let the count of the sections the class should label as "Chocolate Ice Cream"  be x

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E = event of getting "Chocolate Ice Cream" in the spinner ,

then as n(E) = x (as there are x sections with label "Chocolate Ice Cream")

and n(S) = total count of sections (size of sample space)  = 10

Thus, we get probability of event E as:

P(E) = \dfrac{n(E)}{n(S)} = \dfrac{x}{10}

This needs to be equal to 0.3, thus,

0.3 = \dfrac{x}{10}\\x = 3


Thus, the count of the sections the class should label as "Chocolate Ice Cream" is 3.

Learn more about probability here:

brainly.com/question/1210781

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