<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20q%5E%7B2%7D%2B7-%5Cfrac%7B1%7D%7B2%7D%20q%5E%7B2%7D" id="TexFormula1"

Ask question

Ask question

All categories

VashaNatasha [74]

2 years ago

10

title="\frac{3}{4} q^{2}+7-\frac{1}{2} q^{2}" alt="\frac{3}{4} q^{2}+7-\frac{1}{2} q^{2}" align="absmiddle" class="latex-formula">

Simplify this quesstion

2 answers:

Sergeu [11.5K]2 years ago

8 0

1/4q^2 +7
Hope this helps :)

Molodets [167]2 years ago

8 0

Answer:

The correct answer is,

$\frac{ {q}^{2} }{4} + 7$

You might be interested in

Difference in the following polynomials (6x^3 - 2x^2 + 4)<br> -(2x^3 + 4x^2 - 5)

Colt1911 [192]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{4x^3-6x^2+9}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Find \ Difference: \ \left(6x^3\:-\:2x^2\:+\:4\right)-\left(2x^3\:+\:4x^2\:-\:5\right)}$

$\bold{-----------------------}$

$\bold{Remove \ Parenthesis}$

$\bold{6x^3-2x^2+4-\left(2x^3+4x^2-5\right)}$

$\bold{Remove \ Parenthesis \ / \ Simplify}$

$\bold{-\left(2x^3+4x^2-5\right): \ -2x^3-4x^2+5}$

$\bold{Rewrite}$

$\bold{6x^3-2x^2+4-2x^3-4x^2+5}$

$\bold{[Simplify \ 6x^3-2x^2+4-2x^3-4x^2+5] \ 4x^3-6x^2+9}$

$\bold{4x^3-6x^2+9}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

6 0

3 years ago

"Tim's lawn is 20 meters by 30 meters. If Tim can mow 8 square meters of grass per minute, how long will it take him to mow the

frosja888 [35]

One hour and a half

5 0

2 years ago

Help me find the arc length of this. Thank you.

BabaBlast [244]

The red chord is a diameter of the circle, so the length of the blue arc is half the circle's circumference.

The circumference of a circle with diameter $d$ is $\pi d$ , so the circle has circumference $8\pi$ , and so the arc has length $4\pi$ .

4 0

3 years ago

Solve (1/81)^x*1/243=(1/9)^−3−1 by rewriting each side with a common base.

elena55 [62]

Answer:

$x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

Step-by-step explanation:

you have the following formula:

$(\frac{1}{81})^{\frac{x}{243}}=(\frac{1}{9})^{-3}-1$

To solve this equation you use the following properties:

$log_aa^x=x$

Thne, by using this propwerty in the equation (1) you obtain for x

$log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]$

8 0

2 years ago

41/17 rounded to the nearest hendreth

Andrews [41]

Answer:

2.47

Step-by-step explanation:

convert it to a decimal = 2.47058823....

then round that to a nearest hundredth = 2.47

3 0

2 years ago

Read 2 more answers