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Diano4ka-milaya [45]
3 years ago
9

Mateo has y pairs of shoes his brother has 5 fewer than him. write an expression in its simplest form that represent the total a

mount
Mathematics
1 answer:
notka56 [123]3 years ago
7 0
Y-5 thus total is y+5
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Solve the equation x^13-2x^12-x^11+2x^10=0 in the real number system
ASHA 777 [7]

Answer:

x ={0; - 1 ;  2 ;  1}

Step-by-step explanation:

x¹³-2x¹²-x¹¹+2x¹⁰=0

x¹⁰(x³-2x²-x+2)=0

x¹⁰(x+1)(x-2)(x-1)=0

x¹⁰=0    ∨   x+1=0    ∨    x-2=0   ∨   x-1=0

x=0             x= - 1             x= 2          x= 1

3 0
3 years ago
Write a linear inequality in two variables that has (-1, 3) as a solution but does not have (4,0) as a solution.
Stels [109]

Answer:  y ≤ -x + 2

<u>Step-by-step explanation:</u>

There are an infinite number of possible solutions.

Plot the two points, draw any line between them such that the two points are NOT connected, then choose the inequality symbol that shades (-1, 3).

Here is one solution that satisfies the requirements.   y ≤ -x + 2

Here is another: y < -x + 3

And another: y > x + 3

And one more: y ≥ x + 4

3 0
3 years ago
What is the value of y in the equation 5x + 2y = 20, when x = 0.3?
Dimas [21]
Y=9.25 (short answer but hope this helped u)
5 0
3 years ago
Read 2 more answers
Sue deposited $52 into her bank account, so she currently has $12 in her account. What was her balance before the deposit?
Semenov [28]

Answer:

-40

Step-by-step explanation:

12 - 52 = -40

hope this helps...

7 0
3 years ago
Read 2 more answers
Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1
natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(-5-(-2))^2+(3-1)^2}

r=\sqrt{(-5+2)^2+(2)^2}

r=\sqrt{(-3)^2+(2)^2}

On further simplification, we get

r=\sqrt{9+4}

r=\sqrt{13}

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

8 0
3 years ago
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