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finlep [7]
3 years ago
15

What is the equation of the line that passes through the point (-3,-4) and has a slope of 4?

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0
It is =4x+8 that's the answer
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Es posible construir un triángulo rectángulo e isosceles
aniked [119]

Answer:

SI

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which pair of angles shares ray A.F as a common side? DAF and DAB EAF and CAE BAF and EAD BAF and FAD
shtirl [24]

Answer:

BAF and FAD

Step-by-step explanation:

In order for an angle to have A.F as a side, it must have the letters A.F or FA in its name.

In DAF, the angle is made of rays AD and A.F.  In DAB, the angle is made up of rays AD and AB.  This is not the correct pair.

In EAF, the angle is made of rays AE and A.F.  In CAE, the angle is made up of rays AC and AE.  This is not the correct pair.

In BAF, the angle is made of rays AB and A.F.  In EAD, the angle is made up of rays AE and AD.  This is not the correct pair.

In BAF, the angle is made up of rays AB and A.F.  In FAD, the angle is made up of rays A.F and AD.  This is the correct pair.

5 0
3 years ago
Read 2 more answers
A softball team is ordering pizza to eat after their tournament. They plan to order cheese pizzas that cost $ 6 each and four-to
Vlada [557]

Answer:

6x + 10t

Step-by-step explanation:

We know that each cheese pizza (c) is $6, and each four topping pizza (f) is $10.

Knowing this, the total of all the pizzas is going to be 6* the amount of cheese (c) plus 10* the amount of four-toppings.

6x + 10t

8 0
3 years ago
NO LINKS!!! Part 2: Find the Lateral Area, Total Surface Area, and Volume. Round your answer to two decimal places.​
slava [35]

Answer:

<h3><u>Question 7</u></h3>

<u>Lateral Surface Area</u>

The bases of a triangular prism are the triangles.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the triangles (bases).

\implies \sf L.A.=2(10 \times 6)+(3 \times 6)=138\:\:m^2

<u>Total Surface Area</u>

Area of the isosceles triangle:

\implies \sf A=\dfrac{1}{2}\times base \times height=\dfrac{1}{2}\cdot3 \cdot \sqrt{10^2-1.5^2}=\dfrac{3\sqrt{391}}{4}\:m^2

Total surface area:

\implies \sf T.A.=2\:bases+L.A.=2\left(\dfrac{3\sqrt{391}}{4}\right)+138=167.66\:\:m^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=\left(\dfrac{3\sqrt{391}}{4}\right) \times 6=88.98\:\:m^3\:(2\:d.p.)

<h3><u>Question 8</u></h3>

<u>Lateral Surface Area</u>

The bases of a hexagonal prism are the pentagons.

Therefore, the Lateral Surface Area (L.A.) is the total surface area excluding the areas of the pentagons (bases).

\implies \sf L.A.=5(5 \times 6)=150\:\:cm^2

<u>Total Surface Area</u>

Area of a pentagon:

\sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}a^2

where a is the side length.

Therefore:

\implies \sf A=\dfrac{1}{4}\sqrt{5(5+2\sqrt{5})}\cdot 5^2=43.01\:\:cm^2\:(2\:d.p.)

Total surface area:

\sf \implies T.A.=2\:bases+L.A.=2(43.01)+150=236.02\:\:cm^2\:(2\:d.p.)

<u>Volume</u>

\sf \implies Vol.=area\:of\:base \times height=43.011193... \times 6=258.07\:\:cm^3\:(2\:d.p.)

8 0
2 years ago
Hepl me what is the answer to this math question
Luda [366]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
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