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ivanzaharov [21]
3 years ago
5

What is the weight of a bowling ball with a 5 in. radius if we know that one cubic inch weighs 1/100th of a pound?

Mathematics
1 answer:
deff fn [24]3 years ago
7 0

The correct answer is - B. 5.24 lb.

Explanation:

Given is a bowling ball, so it is a sphere.

The radius is given as = 5 inches

Volume of the sphere = \frac{4}{3} \pi r^{3}

Putting r=5 and pi = 3.142 in the above formula, we get

volume = 523.66 cubic inches

Also given is - one cubic inch weighs 1/100th of a pound

So, 523.66 cubic inches will weigh = \frac{523.66}{100}=5.2366

Hence rounding this off we get the weight of the bowling ball as 5.24 lb.

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Answer:

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The type of triangle we’re looking at is a equilateral triangle meaning all sides and all angle measures measure the exact same thing.

With all this information, angle S and T measure 60*
•••••••••••••••••••••••••••••••
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now, we could expand them, but there's no need, since it's just factoring.

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