What is the weight of a bowling ball with a 5 in. radius if we know that one cubic inch weighs 1/100th of a pound?
1 answer:
The correct answer is - B. 5.24 lb.
Explanation:
Given is a bowling ball, so it is a sphere.
The radius is given as = 5 inches
Volume of the sphere =
Putting r=5 and pi = 3.142 in the above formula, we get
volume = 523.66 cubic inches
Also given is - one cubic inch weighs 1/100th of a pound
So, 523.66 cubic inches will weigh =
Hence rounding this off we get the weight of the bowling ball as 5.24 lb.
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This is a 45-90-45 triangle so in order to find the answer we have to multiply the hypotenuse, 6, by the square root of 2 or radical 2. Then multiply top and bottom by radical 2. Then simplify.
Answer:
∠ C = 118°
Step-by-step explanation:
DE = DF , then Δ DEF is isosceles with base angles congruent , then
∠ DEF = ∠ DFE = =
= 62°
∠ DFE and ∠ DFB are adjacent angles on a straight line and sum to 180° , so
∠ DFB = 180° - 62° = 118°
BCDF is a parallelogram ( opposite sides are parallel )
The opposite angles of a parallelogram are congruent , then
∠ C = ∠ DFB = 118°