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OleMash [197]
3 years ago
8

2. Ali is collecting signatures for a petition,

Mathematics
1 answer:
swat323 years ago
7 0

Step-by-step explanation:

Since the options are not clear enough, please kindly see the attached file for more explanation

You might be interested in
How do you increase 300 by 54%?
Vanyuwa [196]
Multiply 300 by 54%= 16,200
Divide 16,200 by 100
= 162.20
Round 162.20 to the nearest whole
= 162
hope this helps.
This is the steps to finding a percent
4 0
3 years ago
Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
Serjik [45]

Answer:

C

Step-by-step explanation:

the side with 12 and on the smaller triangle and the side with 16 on the larger triangle are corresponding.

6 0
3 years ago
What TWO steps do you take to solve the following equation: 5x - 3 = 12
hichkok12 [17]

Answer:

First add 3 to each side

Then divide each side by 5

Step-by-step explanation:

5x - 3 = 12

First add 3 to each side

5x-3+3 = 12+3

5x = 15

Then divide each side by 5

5x/5 = 15/5

x = 3

4 0
3 years ago
Read 2 more answers
Please include how to solve this!! Thanks you!
arlik [135]

Circle=27, triangle=18, and square=26

Start with the second question. If you divide 36 by 2, you get 18 which is the value for the triangle. Now since you know the value of the triange you subtract it from 45. (45-18=27) 27 is the value of the circle. Lastly, subtract 27 from 53 to get the value of the square (53-27=26). Hope this helps!

5 0
3 years ago
Lim x approaches 0 (1+2x)3/sinx
jok3333 [9.3K]

Interpreting your expression as

\dfrac{3(1+2x)}{\sin(x)}

when x approaches zero, the numerator approaches 3:

3(1+2x) \to 3(1+2\cdot 0) = 3(1+0) = 3\cdot 1 = 3

The denominator approaches 0, because \sin(0)=0

Moreover, we have

\displaystyle \lim_{x\to 0^-} \sin(x) = 0^-,\quad \displaystyle \lim_{x\to 0^+} \sin(x) = 0^+

So, the limit does not exist, because left and right limits are different:

\displaystyle \lim_{x\to 0^-} \dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^-} = -\infty,\quad \displaystyle \lim_{x\to 0^+}\dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^+} = +\infty

8 0
3 years ago
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