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3 years ago

Can you guy help me please

1 answer:

7 0

For number 25 it’s x=4 and for 26 it’s x=7

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umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ <em>cross multiply</em>

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

2 years ago

gayaneshka [121]

I think the answer is D but I’m not sure

6 0

3 years ago

Aleksandr [31]

The graph is a good representation of the data.

8 0

3 years ago

In-s [12.5K]

Answer: y = 3x + 5

Look at graph:

4 0

2 years ago

tresset_1 [31]

It would be easier to do A

6 0

3 years ago