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Ksju [112]
3 years ago
5

Please help me answer all parts of the question in the photo.

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0
z_1=4+2i\\z_2=-1+2i\\\overline(z_2)=\sqrt{(-1)^2+(2i)^2}=\sqrt{1-4}=i\sqrt{3}\\ z_1+\overline(z_1)=4+2i+\sqrt{4^2+(2i)^2}=4+2i+\sqrt{16-4}=4+\sqrt{12}+2i\\z_2+\overline(z_2)=-1+2i+\sqrt{(-1)^2+(2i)^2}=-1+2i+\sqrt{1-4}=-1+(2+\sqrt{3})i
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What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard norma
Harlamova29_29 [7]

The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

It is given that the standard normal curve shows the shaded area in the curve.

It is required to find the approximate area of the unshaded region under the standard normal curve.

<h3>What is a normal distribution?</h3>

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

In the curve showing the shaded region area between:

\rm P(1 < Z < 2)

First, we calculate the shaded region area:

From the data given the value of Ф(1) = 0.8413.

P(Z<1)  = 0.8413  and

P(Z<2) =  0.9772

The area of the shaded region:

= P(Z<2) - P(Z<1)

=  0.9772 - 0.8413

= 0.1359

The area of the unshaded region:

= 1 - The area of the shaded region  ( because the curve is symmetric)

= 1 - 0.1359

= 0.8641 ≈ 0.86

Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

Know more about the normal distribution here:

brainly.com/question/12421652

4 0
2 years ago
2. Draw the image of ∆RST under the dilation with scale factor ⅓ and center of dilation at the origin. Label the image ∆R’S’T’.
Alchen [17]
Since center of dilation is the origin, this is easy. Just divide all of the x and y coordinate values by 3. Place the new point on the graph, and draw the triangle.

R' = R(3,6)/3 = (3/3,6/3)=(1,2). So R'(1,2)
S' = S(-3,6)/3 = (-3/3,6/3)=(-1,2). So S'(-1,2)
T' = T(-6,-6)/3 = (-6/3,-6/3)=(-2,-2). So T'(-2,-2)

So you now know the location of the 3 new points. R' at (1,2), S' at (-1,2) and T' at (-2,-2). Simply draw those 3 points on your graph and connect the lines to make a new triangle.

6 0
3 years ago
A jet plane can carry up to 200,000 liters of fuel. It used 130,000 liters of fuel during a flight. What percentage of the fuel
Leto [7]

Answer:

Step-by-step explanation:

65%

Step-by-step explanation:

Given: Full capacity= 200000 litres

          Amount of fuel used during flight= 130000 litres

Now, finding percentage of fuel used on the flight.

∴ Percentage of fuel used=  

Solving it, we will get  

∴ 65% of fuel capacity been used in this flight.

4 0
2 years ago
Read 2 more answers
Use the Pythagorean Theorem to find the distance from Emma's house to the library.
AlladinOne [14]

Answer:square root 130

Step-by-step explanation:

4 0
4 years ago
Please answer seriously!!
Sedaia [141]

Answer:

27. chord

28. radius

29. diameter

30. secant

31. tangent

32. secant

Step-by-step explanation:

I guess thats the correct answer

6 0
2 years ago
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