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pickupchik [31]

4 years ago

13

100 text books increased by 99 percent

2 answers:

Montano1993 [528]4 years ago

8 0

Answer:

Step-by-step explanation:

1

vfiekz [6]4 years ago

4 0

100 increased by 99 would be 100+99 so it would be 199

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QTR is a right triangle TQR is a right triangle QS is an altitude which statements are true

mars1129 [50]

Answer:

A and C

Step-by-step explanation:

for A

QT/RT=ST/QT=QS/QR

There are two QT's in this

so

(QT)^2 = RT * ST

FOR B

there is no RT twice

for C

QR/RT RS/QR

There is a QR twice

so QR^2=RT*RS

FOR D there is no RT twice

(if you have the other answers for this quiz plz give them to me lol)

4 0

3 years ago

Which expression is equivalent to 15 - 5x? select all that apply

m_a_m_a [10]

Choices A and B are correct. To find the equivalent expressions, you would do the distributive property for the choices to
get rid of the parentheses. You would then see which choices match up with 15 - 5x. Hope this helps!
A.) -5x + 15 (yes)
B.) 15 - 5x (yes)
C.) -15 + 5x (no)
D.) 5 - x (no)

3 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

3 years ago

If the domain of the square root function f(x) is x<7, which statement must be true?

Delicious77 [7]

Answer:

The x-term inside the radical has a negative coefficient

Step-by-step explanation:

The argument of a square root should be ALWAYS greater or equal to zero. If the domain of the function is x<7, rearranging, we have: 0<x-7

Therefore the argument is: x-7, and the function is: y = √(x-7)

The statement "The x-term inside the radical has a negative coefficient" is the right answer.

5 0

3 years ago

MATH HELP LEASE WILL GIVE BRAINLIEST!!!

Marysya12 [62]

The answer is (22) hope it helps have a great day

8 0

3 years ago