Question

PLEASE HELP ME WITH THIS

Answer 1

In this question , we have to use sine law, which is

$\frac{sin \ Q}{PR} = \frac{sin \ P}{QR}$

$\frac{sin73}{68} = \frac{sin \ P }{47.6}$

$sin \ P = \frac{47.6 sin 73}{68}$

$P = sin^{-1} ( \frac{ 47.6 sin73}{68}) = 42$

Correct option is b.