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Crank
2 years ago
11

In the diagram, the only figure that could be parallel to line c is ?

Mathematics
2 answers:
Goryan [66]2 years ago
8 0
I believe your answer would be line D.
Novay_Z [31]2 years ago
6 0

<u>Answer-</u>

<em>Line d</em><em> could be parallel to line c.</em>

<u>Solution-</u>

In the given picture, there are 4 lines. Two are on the R plane and 2 are on the Q plane.

Line c and d are on R plane, a and b are on Q plane.

Parallel lines are those lines on a plane which do not meet. Two lines on a plane that do not intersect or touch each other at any point are said to be parallel.

So line a and b are not parallel to c.

Actually c and b are intersecting lines, c and a are skew lines.

As c and d are on a single plane and they don't intersect, so they could be parallel to each other.

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Answer:

<u>Terrance will need a mortgage loan of US$ 174,250</u>

Step-by-step explanation:

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3 years ago
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ella [17]

Answer:

A non-equilateral rhombus.

Step-by-step explanation:

We can solve this graphically.

We start with square:

ABCD

with:

A = (11, - 7)

B = (9, - 4)

C = (11, - 1)

D = (13, - 4)

Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:

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BC =  √( (11 - 9)^2 + (-1 -(-4))^2) = √13

CD =  √( (11 - 13)^2 + (-1 -(-4))^2)  = √13

DA =  √( (11 - 13)^2 + (-7 -(-4))^2) = √13

And we change C by C' = (11, 1)

In the image you can see the 5 points and the figure that they make:

The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.

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