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alisha [4.7K]
3 years ago
9

Simplify each expression using order of operations. (the one that’s circled)

Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

18

Step-by-step explanation:

1. 6x6=36

2. 8+36=44

3. 44/11=4

4. 7x2=14

5. 4+14=18

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Jordyn’s big sister gives her a 10-yard head start before they start racing. If Jordyn can run 1 yard per second, make a table o
erastova [34]

Answer:

I dont know much but she will get 10 yards per 10 seconds

Step-by-step explanation:

5 0
3 years ago
An airplane climbs at an angle of 2.7" from an altitude of 4500 ft to an altitude of 5600 ft. How far does the airplane travel a
Dvinal [7]

Answer:

  23,325 ft, about 4.42 miles

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle, where the side adjacent to the 2.7° angle of climb is the horizontal distance, and the side opposite is the vertical change in altitude. That change is ...

  5600 ft -4500 ft = 1100 ft

and the angle relation is ...

  tan(2.7°) = opposite/adjacent = (1100 ft)/(horizontal distance)

Multiplying this equation by (horizontal distance)/tan(2.7°) gives ...

   horizontal distance = (1100 ft)/tan(2.7°) ≈ 23,325 ft

Dividing this by 5280 ft/mi gives ...

  horizontal distance ≈ 4.42 mi

The airplane travels about 23,325 ft, or 4.42 miles, horizontally as it climbs.

4 0
3 years ago
Y=-6 and 6x+y=8 then
ANEK [815]

Answer:2.3 repeating


Step-by-step explanation:

6x+y=8

6x+-6=8

+6      +6

6x=14

divided by 6

x= 2.3 repeating

6 0
3 years ago
Read 2 more answers
Solve for a. You must write your answer in fully simplified form.
son4ous [18]

Answer:

where is the problem

Step-by-step explanation:

hu

rfgv problem?

3 0
3 years ago
Read 2 more answers
please solve it please solve it please solve it please solve it please solve it please solve it please solve it please solve it
katovenus [111]

Since \alpha and \beta are roots of ax^2+bx+c, we can factorize the quadratic in terms of the roots as

ax^2+bx+c = a(x-\alpha)(x-\beta)

Expanding the right side gives

ax^2+bx+c = ax^2-a(\alpha+\beta)x+a\alpha\beta

so that

\alpha + \beta = -\dfrac ba \\\\ \alpha\beta = \dfrac ca

A polynomial with roots \alpha^2 and \beta^2 would be

(x-\alpha^2)(x-\beta^2)

and expanding this gives

x^2 - (\alpha^2+\beta^2)x+\alpha^2\beta^2

Now,

\alpha\beta = \dfrac ca \implies \alpha^2\beta^2 = (\alpha\beta)^2 = \dfrac{c^2}{a^2}

and

(\alpha+\beta)^2 = \alpha^2 + 2\alpha\beta + \beta^2 \\\\ \implies \alpha^2+\beta^2 = \left(-\dfrac ba\right)^2 -2\left(\dfrac ca\right) = \dfrac{b^2-2ac}{a^2}

So we can write the second quadratic in terms of a,b,c as

(x-\alpha^2)(x-\beta^2) = x^2 - \dfrac{b^2-2ac}{a^2}x + \dfrac{c^2}{a^2}

and to make things look cleaner, scale the whole expression by a^2 to get

\boxed{a^2x^2 + (2ac-b^2)x + c^2}

4 0
3 years ago
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