First, we will find the value of k
We can do this by sybstituting y=24, x=6 in;
y=kx and then solve for k
24= k(6)
divide both-side of the equation by 6
24/6 = k
4 = k
k=4
Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y
y= (4)(5)
y = 20
A possible perimeter for the rectangle would be 28
Area=L x W
40/10=4
Width=4, Length=10
Perimeter=L+L+W+W
4+4+10+10=28
12.4 is the answer for both
Step-by-step explanation:
1. Ampltiude is 1
The period is
is the period
The phase shift is 0
2. The Ampltiude is 2
The period is 2 pi
The phase shift is 1
3. The amplitude is 3
The period is 2 pi/3
The phase shift is -2
4.The amplitude is 2/3
The period is -10pi
The phase shift is 0
5. The Ampltiude is 1
The period is -2 pi
The phase shift is pi
6. The amplitude is 1/4
The period is -4pi
The phase shift is negative 2pi/3
7. The Ampltiude is 3
The period is 4
The phase shift is 8