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svetoff [14.1K]

2 years ago

7

GOLF Sky is a member of her school’s golf team. The table shows her scores from each of her matches. What was her average golf s

core? Round to the nearest tenth if necessary.
Table:
72|69|72
71 |71|69
68|72|68

1 answer:

Fiesta28 [93]2 years ago

8 0

Answer:

72,70,72, 71,71,70,69,72,69

I really didn't understand the question or what to do, but I tried.

Step-by-step explanation:

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PLEASE HELP ME WITH THIS QUESTION ASAP. please and thank you

kotegsom [21]

To solve the given equation, you would need to multiply t by both terms inside the parenthesis.

The equation would be D. (t*14) - (t*5)

3 0

3 years ago

The question is on the image

allochka39001 [22]

2th bounce- 80
5th Bounce- (-)200
9th Bounce- (-)560

Every time the ball bounces it loses 40cm because on the first bounce 160cm-120cm=40cm
And the score goes down by 40 every time and since we go into the negatives the negatives sometimes add on top of each other

5 0

1 year ago

If f(x) = 2x^2 + 2, find f(5)

zlopas [31]

Well, following the order of PEMDAS, I got choice B. 52

For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.

Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.

In this case, you square the number 5, which gives you F(5)=2(25)+2

After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.

Finally, you add them, which results in F=52.

By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.

Anyway, hope this helped! :-)

8 0

3 years ago

Help on this please I’d appreciate it

Cerrena [4.2K]

Answer:

B

Step-by-step explanation:

yes, 12² + 13² = ( $\sqrt{313}$ )²

144 + 169 = 313

313 = 313

3 0

2 years ago

Read 2 more answers

Two horses are ready to return to their barn after a long workout session at the track. The horses are at coordinates H(1,10) an

lana [24]

Distance between points $\left(x_1,y_1\right)$ and $\left( x_2,y_2 \right)$ is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Distance from H to B:

$[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}$ d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.

Distance from Z to B:

$d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}$ units.

Horse Z is closer to the barn.

(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)

6 0

3 years ago