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The rate of flow outward through the hemisphere x² + y² + z² = 9, z >= 0 is zero.
Given that,
Seawater has a density of 1025 kg/m³ and moves at a constant velocity field defined by the equations v = yi + xj, where x, y, and z are measured in meters and the components of V are expressed in meters per second.
We have to find the rate of flow outward through the hemisphere x² + y² + z² = 9, z >= 0.
We know that,
v= yi + xj, and density = 1025 kg/m³
F=1025(yi + xj)
After solving the R(u,v) we get zero.
Therefore, the rate of flow outward through the hemisphere x² + y² + z² = 9, z >= 0 is zero.
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20/100=x/321
20 x 321=100x
20 x 321=6420
6420/100=64.2
Answer:
0
Step-by-step explanation:
We can find the slope by using the slope function
m = (y2-y1)/(x2-x1)
= (-3 - -3)/(-2 - 6)
= (-3+3)/(-2-6)
= 0/-8
= 0
Square both given expressions and add them together. Make use of trig identities.
(sin(a) +sin(b))^2 = sin(a)^2 +2sin(a)sin(b) +sin(b)^2 = 5/3
(cos(a) +cos(b))^2 = cos(a)^2 +2cos(a)cos(b) +cos(b)^2 = 1
Adding, we have
sin(a)^2 +cos(a^2) +2(cos(a)cos(b) +sin(a)sin(b)) +sin(b)^2 +cos(b)^2 = 2 2/3
Of course, the first and last pairs of terms are 1 and 1, and the middle product is 2cos(a-b), so you have
1 + 2cos(a-b) +1 = 2 2/3
cos(a-b) = 1/3
