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3 years ago

13

Daniel fish tank holds 24 liters of water.He uses a 4-liter bucket to fill the tank.How many buckets of water are needed to fill

the tank?

1 answer:

djyliett [7]3 years ago

6 0

Answer: 6-liter bucket are need to fill the tank.

Step-by-step explanation:

24/4= 6

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A figure lies on a coordinate plane with point B located at (2,-5). The figure is rotated 90 degrees counter-clockwise around a

Rufina [12.5K]

<h3>Answer: (12,3)</h3>

======================================================

Explanation:

R is located at (3,4). Move it 3 units to the left and 4 units down to have it move to (0,0). Call this point A. Apply the same translation rule to point B so that (2,-5) moves to (-1,-9). Let's call this point C

Now you'll use the rule $(x,y) \to (-y,x)$ which rotates any point around the origin 90 degrees counterclockwise. So we're rotating C around A.

Point C has the coordinates (-1,-9). When you use the rotation rule $(x,y) \to (-y,x)$ we get $(-1,-9) \to (-(-9), -1) = (9, -1)$ . We'll call this point D

Finally, undo the translation rule done at the start of the problem. So we'll go 3 units to the right and 4 units up to have point D move to point E = (12,3) which is exactly where point B' is located.

Check out the diagram below.

7 0

3 years ago

The average heights of a random sample of 400 people from a city is 1.75 m. It is known that the heights of the population are r

Dimas [21]

Answer:

The 95% confidence interval for the average heights of the population is between 1.7108m and 1.7892m.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So

$\sigma = \sqrt{0.16} = 0.4$

Then

$M = 1.96*\frac{0.4}{\sqrt{400}} = 0.0392$

The lower end of the interval is the mean subtracted by M. So it is 1.75 - 0.0392 = 1.7108m

The upper end of the interval is the mean added to M. So it is 1.75 + 0.0392 = 1.7892m

The 95% confidence interval for the average heights of the population is between 1.7108m and 1.7892m.

4 0

3 years ago

Emily is going to the movies this weekend with some friends. they have a total of $54 to spend. Emily wants a large popcorn that

timurjin [86]

Answer is 7

You have to do

54 - 12= 42

Then divide 42 by 6 which equals 7

3 0

3 years ago

Read 2 more answers

An insured's roof cost $4,000 when installed 5 years ago. It has been damaged by hail and must be replaced. The new roof will co

hoa [83]

Answer:

ACV=$4,500

Step-by-step explanation:

We have that the actual cash value (ACV) is defined as:

$ACV=\dfrac{R\times(E-C)}{E}$

Where:

$ACV =$ actual cash value

$R =$ replacement cost or purchase price of the item

$E =$ expected life of the item

$C =$ current life of the item

Then we have R=$6,000, C=5years, and to find the expected life of the item we can use the depreciating of the roof, then if the roof is depreciating $200 each year we just need to divide $4,000 by $200 to find the expected life of the roof:

$\dfrac{4,000}{200}=20$

Then the espected life of the roof is 20 years, with this result we have all the data, then:

$ACV=\dfrac{\$6,000\times (20-5)}{20}=\dfrac{\$6,000\times (15)}{20}=\dfrac{\$90,000}{20}=\$4,500$

Then the ACV is $4,500

5 0

3 years ago

Eleanor scores 680 on the mathematics part of the SAT. The distribution of SAT math scores in recent years has been Normal with

Katen [24]

Answer:

Elanor's standardized score is 1.19
Gerald's standardized score is 0.72
Elanor has higher score

Step-by-step explanation:

To compare Elanor's and Gerald's math scores, we need to standardize them and calculate their z-scores.

z score can be calculated using the formula

z= $\frac{X-M}{s}$ where

X is the student's score

M is the mean score of the exam

s is the standard deviation of the exam

Elanor's standardized score is:

z(e) = $\frac{680-554}{106}$ ≈ 1.19

Gerald's standardized score is:

z(g)= $\frac{27-24.7}{3.2}$ ≈ 0.72

Since z(e) > z(g), Elanor has higher score

6 0

3 years ago