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2 years ago

4,5,6,7,8 , please hellppppp , i’m stuck . i will mark brainliest to the first person who gets them righttt

Mathematics

1 answer:

Volgvan2 years ago

8 0

4)
ordered pairs : (-5,4)(-3,2)(2,6)(-3,-5) it is not a function because it repeats x’s
5)
ordered pairs : (4,5)(2,5)(1,-3)(-2,-2) it is a function because it is NOT repeating x’s
6)
(2,6)(6,8)(6,10)(8,12) it is not a function because it repeats x’s

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Given: 3x + y = 1.<br> Solve for y. <br> A. y = -3x + 1<br> B.y = -3x - 1<br> C.y = 3x - 1

RUDIKE [14]

Y=-3x+1
So the answer is A. All you're doing is moving the 3x to the opposite side, and because your switching the side, you need to switch the sign. So it's a negative 3x after you solve for y. Solving for y(or any letter) is just getting that letter alone on one side of the equal sign.

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2 years ago

Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3

Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

$f\left(x\right)=\sqrt{x^3-16x}$

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

$x^3-16x\ge 0$

as x³ - 16x ≥ 0

$\left(x+4\right)\left(x-4\right)\ge \:0$

Thus, identifying the intervals:

$-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4$

Thus,

The domain of the function f(x) is:

$x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}$

And the Least Value of the domain is -4.

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2 years ago

8 yards is equal less or greater than 20 feet

vazorg [7]

it is greater than because when you multiply 8 by 3 you get 24

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2 years ago

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const2013 [10]

Since you don't want any leftover items, you have to find the greatest common factor (GCF) of both the crayons and bubbles. Since the highest common factor for both 28 and 12 is 4, the greatest number of gift bags you can make without any leftover items would be 4 gift bags.

Hope I could help.

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