1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksenya-84 [330]
3 years ago
15

Find the mean of the given values,29,42,45,39,36,41,38.What is the answer:39 40 35

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0

Step-by-step explanation:

total number (n) = 7

mean= 270/7

=38.6 = 39

nordsb [41]3 years ago
5 0

Answer:

39 (the first option listed among the possible answers)

Step-by-step explanation:

Recall that the mean is the same as the average of the numbers you have listed, that is the addition of all divided by the number of entries you use:

mean = \frac{29+42+45+39+36+41+38}{7} =\frac{270}{7} =38.57

Therefore, rounding to the nearest integer, our answer s: 39

You might be interested in
The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation
Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

  • Sample size: n = 20
  • Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}    

This gives

P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}

P(x = 11) = 0.0011

Express as percentage

P(x = 11) = 0.11\%

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all  20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}    

This gives

P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0

P(x = 20) = 0.0388

Express as percentage

P(x = 20) = 3.88\%

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

\mu = np

So, we have:

\mu = 20 \times 85\%

\mu = 17

The standard deviation is calculated as:

\sigma = np(1 - p)

So, we have:

\sigma = 20 \times 85\% \times (1 - 85\%)

\sigma = 20 \times 0.85 \times 0.15

\sigma = 2.55

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0
2 years ago
Tony operates a skate rental company. He charges an equipment fee of $3 plus $6 per hour. Which equation represents this linear
slava [35]

Answer: A) y = 6x +3

Step-by-step explanation:

Let x represent the number of hours. $6 per hour can now be written as 6x.

Now, we must account for the $3 flat, fee and add it to 6x, getting 6x + 3

6 0
2 years ago
Josie deposited $450 at the beginning of the month. A payment of $35.20 is automatically deducted each month for her gym members
Alinara [238K]

Answer:

You have told us that there is $450 in Josie's bank account, and she does not make any later deposits or withdraws. You have also told us that the gym deducts $35.20 every one month in fees.

Explanation:

The answer is really easy to find. All you have to do is subtract 35.20 from 450. The problem asks for the amount of money that Josie has in her account at the end of the month - the same month that she put $450 into her account.

Solve:

450 - 35.20

= 414.80

Josie has $414.80 in her bank account at the end of the month.

<h2><u>PLEASE MARK BRAINLIEST! </u></h2>
7 0
3 years ago
What is the simplest form of this expression? (x^-3)^1/3
IrinaK [193]
The simplest form is, <span>x-1 </span>
<span>
</span>
6 0
3 years ago
Read 2 more answers
Javier asks his mother how old a tree in their yard is. His mother says, “The sum of 10 and two-thirds of that tree’s age, in ye
sdas [7]

Answer:

10 + (\frac{2}{3}) a = 50 is the CORRECT equation.

Step-by-step explanation:

The given question is INCOMPLETE.

Javier asks his mother how old a tree in their yard is. His mother says, “The sum of 10 and two-thirds of that tree’s age, in years, is equal to 50.” Javier writes the equation { 10 + 2/3} where a is the tree’s age in years. His equation is not correct. What error did he make?

Now here:

a:  The tree’s age in years.

Also,  “The sum of 10 and two-thirds of that tree’s age, in years, is equal to 50.”

⇒ 10 +  two-thirds of that tree’s age  = 50

\implies 10 + (\frac{2}{3}) a = 50

But in the equation written by Javier, the the third fraction is NOT MULTIPLIED by the age of the tree a in Years.

So, the written equation by Javier is Incorrect.

Now, solving the written correct equation for the value of a, we get:

\implies 10 + (\frac{2}{3}) a = 50\\\implies  (\frac{2}{3}) a = 40\\\implies a = 40 \times  (\frac{3}{2})  = 60\\\implies a  = 60

Hence the correct  age of the tree = 60 years

5 0
3 years ago
Other questions:
  • What is the remainder of -x^3-x^2+3 / x+3
    12·1 answer
  • What is the value ?
    9·1 answer
  • Please help me get this question correct
    5·1 answer
  • Evaluate Tan ^-1 (-1). Enter your answer in radians.<br> Answer here
    7·1 answer
  • Find the point P that partitions the line segment AB given the ratio.
    6·1 answer
  • 3. Anthony got 20 questions correct on his quiz. There were 25
    6·1 answer
  • Q1) find 80% of £120<br> q2) find 60% of £980<br> PLease show working thank uh
    11·1 answer
  • PLEASE HELP I DONT UNDERSTAND IT EXPLAIN YOUR ANSWER THO <br><br><br><br> WOULD IT BE 5
    14·2 answers
  • The population of a village is in the following ratios.
    10·1 answer
  • Can anyone do this i need it rn+ tell me the part when u answer
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!