3 + 4x = 33
-3 on both sides
4x = 30
/4 on both sides
x = 7.5
Answer:
Rod is 7 1/2 years old
Answer:
13.695 m
Step-by-step explanation:
The assumption made here is that the boat/water interface is essentially frictionless, so that the center of mass of the system remains in the same place as the occupant of the boat moves around.
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We can find the sum of the moments of boat and child about the pier end:
(46 kg)(7.6 m) + (80 kg)((7.6 +9.6/2) m) = 1341.6 kg·m
After the child moves, the center of mass of boat and child is presumed to remain in the same place. If x is the new distance from the pier to the child, the sum of moments is now ...
46x +80(x-4.8)* = 1341.6
126x -384 = 1341.6
x = (1341.6 +384)/126 = 13 73/105 ≈ 13.695 . . . meters
The child is about 13.695 meters from the pier when she reaches the far end of the boat.
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* The center of mass of the boat alone is half its length closer to the pier than is the child, so is located at x-4.8 meters.
Answer:
4.93 cm 475.9 mm 4.5 m 47.3 m
Step-by-step explanation:
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Step-by-step explanation:
(a)= 6×2= 12
(b)= -9×2=-18
(c)= 0.7×2=1.4
