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kondor19780726 [428]
3 years ago
11

What is binary in computer science ​

Computers and Technology
1 answer:
timurjin [86]3 years ago
6 0

Answer:

binary is a language.

Explanation:

Well it is a language which uses only two numbers, 0 and 1. This is the language that computer understands. 0 in general means true and 1 in general means false. Binary codes are used for various methods of encoding data.

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When cleaning a computer, you need only worry about what you can see.
almond37 [142]

Answer:

False because the inside could be dirty and cause problems.

Explanation:

4 0
3 years ago
In a relational database, the three basic operations used to develop useful sets of data are:
lesya692 [45]
<span>Which is not a component of a database that describes how data is stored?</span>
6 0
3 years ago
(The Person, Student, Employee, Faculty, and Staff classes) Design a class named Person and its two subclasses named Student and
Mariulka [41]

Answer:

Explanation:

The following code is written in Java and creates all the classes as requested with their variables, and methods. Each extending to the Person class if needed. Due to technical difficulties I have attached the code as a txt file below, as well as a picture with the test output of calling the Staff class.

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3 years ago
How will you keep the buzz going post-hackathon?
Anna71 [15]

Answer:

it would be nice if you gave some form of info here

Explanation:

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8 0
1 year ago
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For f
julia-pushkina [17]

Complete Question:

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

Answer:

a) 51.2 msec.  b) 5.12 msec

Explanation:

If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

  • Tw = K*512* bit time

The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

a) BW  = 1 Mbps = 10⁶ bps

⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

b) BW = 10 Mbps = 10⁷ bps

⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec

5 0
3 years ago
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