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Lyrx [107]
3 years ago
11

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Computers and Technology
1 answer:
beks73 [17]3 years ago
3 0
8wmX si2 jkkajmid di e2 2i2
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Defensive programming is sometimes referred to as _________.
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Why are new versions of applications packages released often ​
stellarik [79]

Answer:

The answer is "new version of application provides more easy to use".

Explanation:

  • In computer science, an application is a program, that is installed on the computer. There are many types of application software, that are "gaming software, working software, programming software, etc." At the end of time users want some new things in software to know users need programmer developed new versions of the software.
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How is your favorite singer and why I will give Brainliest
Lorico [155]

Answer:

Eslabon Armando

His songs hit different ;-;

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Expand and simplify the following expressions. 1/2 [ 2x + 2 ( x - 3)] *​
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4 0
2 years ago
The birthday paradox says that the probability that two people in a room will have the same birthday is more than half, provided
poizon [28]

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

   Random randNum = new Random();

   int people = 5;

   int[] birth_Day = new int[365+1];

   // setting up birthsdays

   for (int i = 0; i < birth_Day.length; i++)

       birth_Day[i] = i + 1;

 

   int iteration;

   // varying number n

   while (people <= 100)

   {

       System.out.println("Number of people: " + people);

       // creating new birth day array

       int[] newbirth_Day = new int[people];

       int count = 0;

       iteration = 100000;

       while(iteration != 0)

       {

           count = 0;

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               // generating random birth day

               int day = randNum.nextInt(365);

               newbirth_Day[i] = birth_Day[day];

           }

           // check for same birthdays

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               int bday = newbirth_Day[i];

               for (int j = i+1; j < newbirth_Day.length; j++)

               {

                   if (bday == newbirth_Day[j])

                   {

                       count++;

                       break;

                   }

               }

           }

           iteration = iteration - 1;

       }

       System.out.println("Probability: " + count + "/" + 100000);

       System.out.println();

       people += 5;

   }

}

}

4 0
3 years ago
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