The way I see it is like this:
He ended with $42.15 -- the last thing that he did before that was buy the umbrella
$42.15 + $23.75 (umbrella) = $65.90
The next thing backwards in order is that he spent "half of his remaining money on a painting", so what he has left is one half what he had before he bought the painting.
$65.90 + $65.90 (cost of the painting) = $131.80
Before that, he spent $25 on dinner and $20 on a cab. So we add those all up:
$131.80 + $25 (dinner) + $20 (cab) = $176.80 (how much money he had at the start of the weekend)
To write it as a single equation:
$42.15 = -$23.75 + (-$25.00 + -$20.00)/2
Answer:
3+5 is the answer
im not sure if this is right
5-8=3
thats the answer to the expression but u need an addition expression for that so
3+5=8
the difference of a subtraction equation plus the lowest number in the expression is equal to the highest number in the in e subtraction expression
hope this helps
can i get brainliest pretty please
Answer:
B
Step-by-step explanation:
Our equation is x² + 7x - 4 = 0. We need to use the quadratic formula, which states that for a quadratic formula of the form ax² + bx + c = 0, then the zeroes/solutions are:
or
.
Here, a = 1, b = 7, and c = -4. Plug these in:
![x=\frac{-b+\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
![x=\frac{-7+\sqrt{7^2-4*1*(-4)} }{2*1}=\frac{-7+\sqrt{49+16} }{2} =\frac{-7+\sqrt{65} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-7%2B%5Csqrt%7B7%5E2-4%2A1%2A%28-4%29%7D%20%7D%7B2%2A1%7D%3D%5Cfrac%7B-7%2B%5Csqrt%7B49%2B16%7D%20%7D%7B2%7D%20%3D%5Cfrac%7B-7%2B%5Csqrt%7B65%7D%20%7D%7B2%7D)
OR
![x=\frac{-b-\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
![x=\frac{-7-\sqrt{7^2-4*1*(-4)} }{2*1}=\frac{-7-\sqrt{49+16} }{2} =\frac{-7-\sqrt{65} }{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-7-%5Csqrt%7B7%5E2-4%2A1%2A%28-4%29%7D%20%7D%7B2%2A1%7D%3D%5Cfrac%7B-7-%5Csqrt%7B49%2B16%7D%20%7D%7B2%7D%20%3D%5Cfrac%7B-7-%5Csqrt%7B65%7D%20%7D%7B2%7D)
Thus, the answer is B.
(x+5)(x+5)
x^2+10x+25(2x-7)
2x^3+20x^2+50x-7x^2-70x-175= 2x^3+13x^2-20x-175