Let g(x)=2x and h(x)=x^2+4 (g o h)(0)

1 answer:

4 0

Answer would be 0 because whatever you get when you plug in g&h in the equation you have to multiply that by 0. And a number multiplied by 0 is always 0.
Hope this helped. Have a great day!

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Determine whether each function is linear or quadratic. Identify the quadratic, linear, and constant terms. g(x)=-2 x²-3(x-2)

valentinak56 [21]

The function g(x) is a quadratic function:

Its quadratic term is -2x²
Its linear term is - 3x
Its constant is 6

<h3>What are functions?</h3>

Functions are algebraic expressions that have at least two variables, in order to make their visual representation through a graph and evaluate their behavior.

This problem deals with linear or quadratic functions, and these differ in the degree of the exponent of the variable:

1 : linear

2 : quadratic

The function:

g(x) = -2x² - 3(x- 2).

g(x) = -2x² - 3x + 6 , we have a quadratic function.

Its quadratic term is -2x²
Its linear term is - 3x
Its constant is 6

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11 months ago

What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$