To compare you should make the down part equal first
27/45 < 30/45
1.) 5x + 10y = 15 => x + 2y = 3 => 3x + 6y = 9
2.) -9x - 12y = 6 => 9x + 12y = -6 => 3x + 4y = -2
3.) -2x + 4y = -5 => 2x - 4y = 5 => 4x - 8y = 10
The attached image is the rhombus in question.
To start, a rhombus will have perpendicular bisectors.
With that, we know that the section where these bisectors cross will create 90 degree angles.
So now we have angles: x, (x-10), and 90.
A triangle will total 180 degrees in total. So if we add up all of these angles, it will total to exactly 180.
In other words: 90+x+(x-10)=180.
So, in this situation, we want to isolate the variables, and find the value of x.
This is the easy part:
Here's that equation again
90+x+(x-10)=180
Subtract 90 from both sides
90-90+x+(x-10)=180-90
x+(x-10)=90
Add 10 to both sides
x+x-10+10=90+10
x+x=100
2x=100
Divide by 2 on both sides
2x/2=100/2
x=50
There's your x value.
Answer:
Its 255+x=180 => so x=105
Answer:
2 and 12 have same chance of occurring
3 and 11
4 and 10
5 and 9
6 and 8
Each pair has same occurrence chance
Step-by-step explanation:
Here, we are interested in calculating knowing the sums that have an equal chance of occurrence.
Firstly, we need a sample space. A sample space refers to the set of all possible results.
Please check attachment for this
From the sample space we have 36 results;
Let’s list the outcomes and the number of times they all appear;
1- 0
2- 1
3- 2
4-3
5-4
6-5
7- 6
8- 5
9-4
10-3
11- 2
12-1
From the above, we can see that;
2 and 12 have same chance
3 and 11
4 and 10
5 and 9
6 and 8