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Pie
3 years ago
8

A test for the presence of a certain disease has probability 0.2 of giving a false-positive result (indicating that an individua

l has the disease when this is not the case) and probability 0.1 of giving a false-negative result. Suppose that 10 individuals are tested, 5 of whom have the disease and 5 whom do not. Let X be the number of positive readings that result.
a. Explain why X does not have a binomial distribution.

b. Find the probability that exactly 3 of the 10 test results is positive?

Mathematics
1 answer:
drek231 [11]3 years ago
4 0
For the part b of the question please find the attached image.

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Answer:

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Step-by-step explanation:

Given the expression cotθ+√3=0

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cotθ = -√3

Since cotθ = 1/tanθ

1/tanθ = -√3

Reciprocate both sides:

tanθ = -1/√3

θ = tan^-1(-1/√3)

θ = -30°

Since the angle is negative, and tanθ is negative in the second and fourth quadrant.

In the second quadrant;

θ = 180-30

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Since 180° = πrad

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In the fourth quadrant;

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Since 180° = πrad

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330° = 11π/6 rad

Hence the solutions are 5π/6 rad and 11π/6 rad.

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