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dezoksy [38]
3 years ago
5

Evaluate 90 divided by X to the second power + y

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer:  =34

=3⋅3⋅3⋅3

=81

For example, 3 to the power of -4:

=3−4

=134

=13⋅3⋅3⋅3

=181

=0.012346

Step-by-step explanation: the solution is expanded when the base x and exponent n are small enough to fit on the screen. Generally, this feature is available when base x is a positive or negative single digit integer raised to the power of a positive or negative single digit integer. Also, when base x is a positive or negative two digit integer raised to the power of a positive or

negative single digit integer less than 7 and greater than -7.

hopefully this is right :/

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vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) PR^{2} =PS*PT

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

PR^{2} =PS*PT

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u>  states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

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3 years ago
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