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dezoksy [38]
2 years ago
5

Evaluate 90 divided by X to the second power + y

Mathematics
1 answer:
Arlecino [84]2 years ago
4 0

Answer:  =34

=3⋅3⋅3⋅3

=81

For example, 3 to the power of -4:

=3−4

=134

=13⋅3⋅3⋅3

=181

=0.012346

Step-by-step explanation: the solution is expanded when the base x and exponent n are small enough to fit on the screen. Generally, this feature is available when base x is a positive or negative single digit integer raised to the power of a positive or negative single digit integer. Also, when base x is a positive or negative two digit integer raised to the power of a positive or

negative single digit integer less than 7 and greater than -7.

hopefully this is right :/

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Dividing the polynomial P(x) by x-6 yields a quotient by Q(x) and a remainder of 5.
bazaltina [42]

Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.

As given in the question,

P(x) be the given polynomial

Dividing P(x) by divisor (x-6) we get,

Quotient = Q(x)

Remainder = 5

Relation between polynomial, divisor, quotient and remainder is given by :

P(x) = Q(x)(x-6) + 5   __(1)

Given Q(-6) = 3

Put x =-6 we get,

P(-6) = Q(-6)(-6-6) +5

⇒ P(-6) = 3(-12) +5

⇒ P(-6) =-36 +5

⇒ P(-6) = -31

Now x =6 in (1),

P(6) = Q(6)(6-6) +5

⇒ P(6) = Q(6)(0) +5

⇒ P(6) = 5

Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.

The complete question is:

Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).

Learn more about polynomial here

brainly.com/question/11536910

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Step-by-step explanation:

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